replace value in php array with given index

Question

I have a problem on replacing a value in array with exact given index. To be exact, I'd like to replace a string in array[2] with a new number but I don't have an idea. So please have a look on my resources :

pos:0 //position of index in array 
id:498 //id of a field
new:6300 //new value to replace in an array
cost:6200-5200-4600-5600-4100 //the array

From above, I'd like to replace a string indexes "0" in "cost" with a new string from "new" so the expected result should be :

6300-5200-4600-5600-4100

I tried to search for everywhere but there's nothing return but array_search - which is not what i'm looking for. Please advise.

How is you array look? What you has here is not much as PHP code, but normal if you has a array you can access/replace a value by use $array[$index] = $newvalue; — FIG-GHD742
– FIG-GHD742, Commented Sep 13, 2012 at 8:39

Mihai Iorga · Accepted Answer · 2012-09-13 08:39:28Z

8

$pos = 0;                            // position
$new = 6300;                         // new value
$cost = '6200-5200-4600-5600-4100';  // string
$cost = explode('-', $cost);         // make it array
$cost[$pos] = $new;                  // change the position $pos with $new
$cost = implode('-', $cost);         // return new $cost
// 6300-5200-4600-5600-4100

answered Sep 13, 2012 at 8:39

Mihai Iorga

39.8k17 gold badges109 silver badges109 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Wilf Over a year ago

@Mihai lorga I've tried your code which seems to be clearest. But the result is a bit weird - the value added up. It becomes six arrays instead of five. Here's the code:

code  room_rate_updatez.php?rate|502|6200-5200-4600-5600-4100|3=5500 foreach($_GET as $key=>$_val){ 	list($_name,$_id,$_cost,$_pos)=explode("|",$key);  	$cost = explode('-', $_val);         // make it array 	$cost[$_pos] = $_cost;                  // change the position $pos with $new 	$cost = implode('-', $cost);         // return new $cost  	echo "new cost : ".$cost; //new cost : 5500-6200-5200-4600-5600-4100 }

Mihai Iorga Over a year ago

But it should be $cost = explode('-', $_cost);

Wilf Over a year ago

@Mihai I've got it. My fault. I confused my own var - swap between $cost and $new so the the array doesn't understand where to replace. Regards,

b1919676 Over a year ago

Easy. Good job, buddy.

Night2 · Accepted Answer · 2012-09-15 05:47:50Z

1

It's so simple:

<?php

$array = array(
    6200, 
    5200, 
    4600, 
    5600, 
    4100
);

$pos = 0;
$new = 6300;

$array[$pos] = $new;

?>

edited Sep 15, 2012 at 5:47

answered Sep 13, 2012 at 8:41

Night2

1,1539 silver badges18 bronze badges

4 Comments

Himanshu Over a year ago

This is your first post. So it came under beta review - first posts. To review it we have to edit, vote, flag the post. I found no fault in your post. So just edited and checked it as fine. :)

Himanshu Over a year ago

And instead of updating it again as old, you can use rollback function to undo edit.

Night2 Over a year ago

Thanks for the info, I'm new here and didn't know about "rollback function" ... :)

Himanshu Over a year ago

You need to visit Meta Stack Overflow to know more about Stack Overflow.

Mike Aski · Accepted Answer · 2012-09-13 08:39:58Z

0

Try this:

$the_array[$pos] = $new

edited Sep 13, 2012 at 8:39

Mike Aski

9,2364 gold badges48 silver badges66 bronze badges

answered Sep 13, 2012 at 8:39

JvdBerg

21.8k8 gold badges40 silver badges55 bronze badges

1 Comment

Mike Aski Over a year ago

Added syntax color - but no color appeared... :)

Collectives™ on Stack Overflow

replace value in php array with given index

3 Answers 3

4 Comments

4 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

4 Comments

4 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related