jQuery - checking the order of a numeric array

Question

Using jQuery is there a function that will tell me if the contents of a numeric array are in number order? For example;

[2,5,7,8,9] would return true [5,2,7,8,9] would return false

Scenario: I have an UL which is populated from mysql, the li items are text statements that have been randomly displayed, the id of the li is the rank order number the item should be for a correct sequence. The user then has to reorder the items by drag and drop using jQuery sortable. When the item is dropped I want jQuery to grap the reordered items via serialize into an array which I can then check to see if they are in numeric order which would indicate a correct answer. I've got everything working and I can pass the results back to php to validate to then show the answer in a separate div but I would like to do the checking on the client using jQuery rather than posting back to the server.

Treat me gently I'm a newbie

George Reith · Accepted Answer · 2012-10-11 11:11:35Z

1

Here you go try this.

var arr1 = [5,2,7,8,9];
var arr2 = [2,5,7,8,9];

function isNumeric(arr) {
   for (var i = 0; i < arr.length - 1; i++) {
      if (arr[i] > arr[i + 1]) {
         return false;
      }
   }
   return true;
}

console.log(isNumeric(arr1));
console.log(isNumeric(arr2));

edited Oct 11, 2012 at 11:11

answered Oct 11, 2012 at 8:54

George Reith

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1 Comment

user1737416 Over a year ago

Spot on - thank you very much - I did kind of get there when i tried but was missing the expertise.

Sender · Accepted Answer · 2012-10-11 09:04:26Z

0

var array1 = [1, 2, 3, 4, 5, 6];
var array2 = [1, 2, 4, 3, 5, 6];

console.log(checkArrayOrder(array1 ,array2));

function checkArrayOrder(array1 ,array2)
{
    for (var i = 0; i<array2.length; i++) {
        if (array2[i] != array1[i]) {
           return false;
            break;
        }//if close
    }//for close
    return true;
}

Check this FIDDLE

answered Oct 11, 2012 at 9:04

Sender

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