JQuery inArray returning true

Question

var arr = [ "One", "Two", "Three" ];

$('select[name="class"]').change(function() {
    if (jQuery.inArray("blah blah", arr)) {
        alert("OK");
    }
});

this is alerting "OK", yet "blah blah" isn't in the array... what am I doing wrong?

Gromer · Accepted Answer · 2012-10-11 20:20:48Z

9

The jQuery.inArray function always returns a value:

Description: Search for a specified value within an array and return its index (or -1 if not found).

Docs: http://api.jquery.com/jQuery.inArray/

Change your code to:

if (jQuery.inArray('blah blah', arr)) >= 0) {
    alert('Ok');
}

answered Oct 11, 2012 at 20:20

Gromer

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Comments

mgraph · Accepted Answer · 2012-10-11 20:20:24Z

3

try :

if (jQuery.inArray("blah blah", arr) >-1) {

instead of :

if (jQuery.inArray("blah blah", arr)) {

answered Oct 11, 2012 at 20:20

mgraph

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Comments

Ryan Kinal · Accepted Answer · 2012-10-11 20:20:34Z

3

jQuery.inArray returns -1 if the item is not found. Unfortunately, -1 is a truthy value in JavaScript.

Check for -1 and you're good.

answered Oct 11, 2012 at 20:20

Ryan Kinal

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