Print JSON object with jQuery

Question

I have some JSON data looking like this:

"Extras": {
  "T01": "Value 1",
  "T02": "Value 2",
  "T03": "Value 3",
  // etc.
}

I need each of these values in a list, and so I've tried this:

$.each(data.result, function(i){
  $("#result").append('<li>'+data.result.Extras[]+'</li>');
});

Which obviously doesn't work, I just can't seem to figure out what to do. I've tried data.result.Extras with no luck (as I just get [object][Object]).

Any ideas what I can do to get all of the values in a list? Thanks!

Don't forget to tick the answer as the correct one though.

Fabián
– Fabián

2015-11-13 22:30:57 +00:00
Commented Nov 13, 2015 at 22:30 — Fabián
– Fabián, Commented Nov 13, 2015 at 22:30

Selvakumar Arumugam · Accepted Answer · 2012-10-31 13:51:03Z

5

You are iterating the data.result, I believe you need to iterate the Extras.

$.each(data.result.Extras, function(k, v){
  $("#result").append('<li>'+v+'</li>');
});

Note: In the above function k is key and v is value in the object Extras. For ex: For the first iterate k would be T01 and v would be Value 1.

The above should produce and output of

<ul id="result">
   <li>Value 1</li>
   <li>Value 2</li>
   <li>Value 3</li>
</ul>

answered Oct 31, 2012 at 13:51

Selvakumar Arumugam

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Comments

Yashpal Singla · Accepted Answer · 2012-10-31 13:55:39Z

2

Try using eval method to convert JSON string, it will give you an obj of JSON, which you can use to get values of each property of JSON String like 'TO1' ,'TO2'

for e.g

var jsonstr = '"Extras": { "T01": "Value 1", "T02": "Value 2", "T03": "Value 3"}';
var obj = eval(jsonstr);
alert(obj.TO1);

answered Oct 31, 2012 at 13:55

Yashpal Singla

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