Ubuntu shell script getting error

Question

I am developing simple shell script which copy all my present directory files to backup directory which will be exist in present working directory. now i'm getting error when i pass more then one condition in if.

#!/bin/bash
filename=nx.pdf
for i in *;
 do
 echo $i;
 if [ $i == backup || $i == $filename ] ; then
    echo "Found backup."
 else
 echo "Part 2"
 cp -rf $i backup
 fi
 done

I am getting error

asd.sh: line 6: [: missing `]'
asd.sh: line 6: ==: command not found
Part 2
deployee.sh
asd.sh: line 6: [: missing `]'
asd.sh: line 6: ==: command not found
Part 2

bidifx · Accepted Answer · 2012-11-02 08:23:50Z

1

The compare operator is = (as defined in POSIX). But == works on some shells as well. Something like this should work:

if [ $i = backup ] || [ $i = $filename ] ; then

answered Nov 2, 2012 at 8:23

bidifx

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pitseeker · Accepted Answer · 2012-11-02 08:17:52Z

1

You should quote $i in "". Otherwise you get syntax errors for filenames with blanks.

answered Nov 2, 2012 at 8:17

pitseeker

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1 Comment

Hitul Mistry Over a year ago

If i do { if [ $i == backup ] ; then echo "Found" then i'm not getting errors.

choroba · Accepted Answer · 2012-11-02 08:27:56Z

1

To be able to use || and && in conditions, you have to use the double square brackets:

if [[ $i == backup || $i == $filename ]] ; then

answered Nov 2, 2012 at 8:27

choroba

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