PHP stdclass json decode

Question

I'm trying to get a few values from a json_decode output. I have a script that connects to Tumblr API after granting access. I have gotten to this point after decoding the object stdClass. The problem I'm having now is trying to echo out only the "name" of the blog and "follower" count. The example below has two blogs instead of one. So the blogs name are "blogone" and "blogtwo" in the example below.

 {"meta":{"status":200,"msg":"OK"},"response":{"user":{"name":"blogone","likes":0,"following":0,"default_post_format":"html","blogs":[{"name":"blogone","url":"http:\/\/blogone.tumblr.com\/","followers":234,"primary":true,"title":"Untitled","description":"","admin":true,"updated":1354139573,"posts":0,"messages":0,"queue":0,"drafts":0,"share_likes":true,"ask":false,"tweet":"N","facebook":"N","facebook_opengraph_enabled":"N","type":"public"},{"name":"blogtwo","url":"http:\/\/blogtwo.tumblr.com\/","followers":0,"primary":false,"title":"dfgdfg","description":"","admin":true,"updated":0,"posts":0,"messages":0,"queue":0,"drafts":0,"share_likes":false,"ask":false,"tweet":"N","facebook":"N","facebook_opengraph_enabled":"N","type":"public"}]}}}

The questions is how do I echo out the blog "name" and "follower" count per each blog. Sometimes there is only one blog and sometimes there can be multiple blogs.

Thank you.

Sergey Eremin · Accepted Answer · 2012-11-29 10:50:56Z

1

$jsonString = '{"meta":{"status":200,"msg":"OK"},"response":{"user":{"name":"blogone","likes":0,"following":0,"default_post_format":"html","blogs":[{"name":"blogone","url":"http:\/\/blogone.tumblr.com\/","followers":234,"primary":true,"title":"Untitled","description":"","admin":true,"updated":1354139573,"posts":0,"messages":0,"queue":0,"drafts":0,"share_likes":true,"ask":false,"tweet":"N","facebook":"N","facebook_opengraph_enabled":"N","type":"public"},{"name":"blogtwo","url":"http:\/\/blogtwo.tumblr.com\/","followers":0,"primary":false,"title":"dfgdfg","description":"","admin":true,"updated":0,"posts":0,"messages":0,"queue":0,"drafts":0,"share_likes":false,"ask":false,"tweet":"N","facebook":"N","facebook_opengraph_enabled":"N","type":"public"}]}}}';
$jsonObject = json_decode($jsonString);
$result = '';
foreach ($jsonObject->response->user->blogs as $blog) {
    $result .= $blog->name . ' - ' . $blog->followers . '<br/>' . "\n";
}
echo $result;

answered Nov 29, 2012 at 10:50

Sergey Eremin

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1 Comment

chillers Over a year ago

Wow this is a first for me. First answer that worked correctly first time! Thank you and now I understand how it works. :D

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