how to use a javascript function to return an object in a node module

Question

I have a problem in which i'm using a file to hold a list of modules and requiring this list in one call in my nodejs server. I want to use the modules in the list in a specific way.

modules.js -

Mods = {
  mymodule: require('./mymodule.js')
}

exports.f = function() {
  return Mods;
}

index.js -

f = require('./modules.js').f;

f().mymodule.echo("Hello World");

so instead of how i'm using f() now i want to put the name of the module i'm calling directly into the function so I can do things like this:

f = require('./modules.js').f;

f('mymodule').echo("Hello World");

I've tried a number of different experiments but can't get it to work, is it possible to do this in javascript?

Captain Zero, I suggest you work on your name, over.

jAndy
– jAndy

2012-12-03 13:54:03 +00:00
Commented Dec 3, 2012 at 13:54 — jAndy
– jAndy, Commented Dec 3, 2012 at 13:54

Esailija · Accepted Answer · 2012-12-03 13:55:24Z

1

Well, if you do this:

var Mods = {
    mymodule: require('./mymodule.js');
}

module.exports = function( name ) {
    return Mods[name];
};

You can then do:

var f = require( "./modules.js"); //no .f required

f( "mymodule" ).echo( "Hello world");

answered Dec 3, 2012 at 13:55

Esailija

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Comments

LarZuK · Accepted Answer · 2012-12-03 14:03:36Z

1

I would say more ... ^^

var Mods = {
    mymodule: require('./mymodule.js');
}

module.exports = function( name ) {
  if( !name ) return Mods;
  return Mods[name];
};

answered Dec 3, 2012 at 14:03

LarZuK

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Comments

davidpfahler · Accepted Answer · 2012-12-03 14:22:20Z

1

Edit: I was asked to explain my answer and I'm pleased to do so. The key to the solution is what is called the bracket notation. This term refers to the ability to access a property on an object in JavaScript using a variable. In the code below you can see how the property of the object Mods is accessed using [name] where name is a variable containing the name of the property as a string.

Mods = {
  mymodule: require('./mymodule.js');
}

exports.f = function(name) {
  return Mods[name];
}

edited Dec 3, 2012 at 14:22

answered Dec 3, 2012 at 13:56

davidpfahler

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1 Comment

cem Over a year ago

Please think about adding a comment to your code only answer.

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