detect attribute of variable - jquery

Question

I am working on a script and not sure why this isn't working

function moveIn($selector) {
if( $( $selector[left] ) != null ){
    $direction = 'left';
}else{
    $direction = 'right';
}

This is does work:

if( $( '#hello[left]' ) != null ){

This is essentially what I am trying to get spit out. It seems the brackets are causing the problem. How else would this be written? Tips for future coding? Thanks

Entire function:

function moveIn($selector) {
if( $( $selector + '[left]' ) != null ){
    $direction = 'left';
}else{
    $direction = 'right';
}
var animation = {};
    animation[$direction] = 0;
$($selector).animate(animation, 1500);
}

Tip, you shouldn't put $ in front of nearly all your variables; it may have some usefulness if it's a jQuery object. — Ja͢ck
– Ja͢ck, Commented Dec 21, 2012 at 3:30

Niet the Dark Absol · Accepted Answer · 2012-12-21 03:21:45Z

3

Assuming you're passing "#hello" as the selector, you are then trying to get the left property of a string, which doesn't exist.

"#hello[left]", on the other hand, searches for an element with the ID hello and a left attribute.

They are not the same. Try $selector+"[left]"

answered Dec 21, 2012 at 3:21

Niet the Dark Absol

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5 Comments

EZDC Over a year ago

Yes that worked but my function still isn't working right. From what you see there should that work? if the selector has the left attribute fill the direction variable with the string left else make it right...?

Niet the Dark Absol Over a year ago

Yes, but what are you doing with the $direction variabe?

Niet the Dark Absol Over a year ago

Okay, what are the initial values of the left and right positions?

EZDC Over a year ago

left is -260px right is -250px. they are two boxes that slide in from the left and right

EZDC Over a year ago

let us continue this discussion in chat

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