JSON parseerror return from AJAX

Question

I'm doing an AJAX call like so:

function getEvents(info){
  $.ajax({
    url: 'get_all_events.php',
    data: {year: info['year'],month: info['month']},          
    type: 'POST',
    dataType: 'json',
    success: function (result) {
        alert(JSON.stringify(result));
    },
    error: function(XMLHttpRequest, textStatus, errorThrown) {
        console.log(XMLHttpRequest.statusText);
        console.log(textStatus);
        console.log(errorThrown);
    }
});
}

Which works on the initialization of the calendar app I'm developing. I create an object 'info' and assign it month/date etc... then when the user presses 'Previous' or 'Next' it reassigns certain variables of the 'info' object and calls getEvents again. I tried re-writing my query, rewriting my AJAX call, adding contentType... nothing seems to work.

Did you check, while re-assigning the values in info object, what values do it contain, and what is the value of result? Check these values using console. — Nishu Tayal
– Nishu Tayal, Commented Feb 10, 2013 at 16:04
Yes, right before I send them out to the AJAX call, I verified that the JavaScript object 'info' contains the right values (which it does). — Jish
– Jish, Commented Feb 11, 2013 at 16:20

AdityaParab · Accepted Answer · 2013-02-10 15:59:58Z

1

see if there are any errors in the console. Also make sure, your get_all_events.php returns the valid JSON string. When you specify dataType:'json' jQuery will automatically parse the returned data. If the data that is returned is not a valid JSON this error is thrown.

How to check?

Do one thing. Remove dataType:'json', attribute from your $.ajax() call... console.log(result) in your success handler... Copy the response text from console and paste it inside some online JSON validator (jsonlint.com) if there is and error, update get_all_events.php on server side to echo the valid JSON

answered Feb 10, 2013 at 15:59

AdityaParab

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1 Comment

Jish Over a year ago

Fantastic idea, I will try this tonight. If this isn't the case, I will setup my debug mode and release the link in an update of my question. Thank you for your suggestion.

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