php private array access from member function

Question

When I run this code, I get only "in constructor" being printed out.

Why am I not seeing the array being printed out?

Apache log shows no errors. PHP syntax checkers show no errors.

<?php
//---- User Class ----      
class User {
    private $list;

    function __construct() { 
        echo "in constructor";
        $this->$list = array(1, 2, 5);
        }

    function printAll() {
        print_r($this->$list);
    }

}   // end Class  

$foo = new User(); 
$foo->printAll();
?>

silly · Accepted Answer · 2014-09-16 07:38:20Z

5

a $ to much, try this

When I run this code, I get only "in constructor" being printed out.

Why am I not seeing the array being printed out?

Apache log shows no errors. PHP syntax checkers show no errors.

class User {
    private $list;

    function __construct() { 
        echo "in constructor";
        $this->list = array(1, 2, 5);
        }

    function printAll() {
        print_r($this->list);
    }
}

edited Sep 16, 2014 at 7:38

answered Feb 21, 2013 at 16:05

silly

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2 Comments

Biketire Over a year ago

maybe you should make the function public? public function printAll(){} (this is a wild guess)

Dissident Rage Over a year ago

Missing a closing bracket on printAll().

RiG SEO Service · Accepted Answer · 2013-12-01 06:12:21Z

0

Yes $this->varname is the proper syntax which we mix up some times.

 class Cname {
    var $name;

     function setName($nam)
     {
         $this -> name = $nam;
     }
  }

answered Dec 1, 2013 at 6:12

RiG SEO Service

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