my javascript variables wont add correctly

Question

im having a problem adding these variables lets say 'pce'=100 and 'epbcac'=200 my result is 100200 instead of 300 what am i doing wrong thanks,

var pce = $('#pce').val();
var epbcac=$('#epbcac').val();

var results12 = pce + epbcac;

$('#tc').val(results12);

Community · Accepted Answer · 2020-06-20 09:12:55Z

4

You are adding strings. You need to make them ints parseInt(string, radix).

var results12 = parseInt(pce,10) + parseInt(epbcac,10);

As @Joe mentioned radix is optional, but if you dont specify it the browser could use a different radix and could cause unpredictable behavior.

Alternatively, as @DavidMcMullin suggested a Savvier way to do it is to use the unary + operator:

var results12  = +pce + + epbcac

Radix is the base of the number system. Meaning the numbers that make up the system:

Binary: radix=2
01010101

Decimal: radix=10
0123456789

Hex: radix=16
0123456789ABCDEF

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Mar 1, 2013 at 20:03

Nix

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6 Comments

Joe Over a year ago

I would also specify the radix, parseInt(pce, 10); just in case.

j08691 Over a year ago

Don't forget to specify the radix.

Ben McCormick Over a year ago

@user2120124 actually he was first.

Arkadiusz 'flies' Rzadkowolski Over a year ago

Nix was first by a few seconds actually.

Frances McMullin Over a year ago

the unary + operator would be another option, if you feel like being more concise, although it also more cryptic... +pce + +epbcac

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Arkadiusz 'flies' Rzadkowolski · Accepted Answer · 2013-03-01 20:04:07Z

0

Use parseInt(pce); and parseInt(epbcac); before summing it up.

answered Mar 1, 2013 at 20:04

Arkadiusz 'flies' Rzadkowolski

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1 Comment

Amareswar Over a year ago

Have proper radix while parsing int. for example parseInt(pce, 10);

Ben McCormick · Accepted Answer · 2013-03-01 20:07:52Z

0

As others said, use parseInt, but ideally use

parseInt(pce,10) + parseInt(epbcac,10)

otherwise strings with leading zeros in the form "012" will be parsed incorrectly as hex digits and the addition won't work correctly.

answered Mar 1, 2013 at 20:07

Ben McCormick

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