Java, replace string numbers with blankstring and remove everything after the numbers

Question

I have strings like:

Alian 12WE

and

ANI1451

Is there any way to replace all the numbers (and everything after the numbers) with an empty string in JAVA?

I want the output to look like this:

Alian

ANI

Use regular expression to search the first index of number and then use substring(0,index) .. google it on how to use regex in java and substring method. Enjoy coding :) — asifsid88
– asifsid88, Commented Mar 9, 2013 at 17:11

1218985 · Accepted Answer · 2013-03-09 17:32:40Z

7

With a regex, it's pretty simple:

public class Test {

    public static String replaceAll(String string) {
        return string.replaceAll("\\d+.*", "");
    }

    public static void main(String[] args) {
        System.out.println(replaceAll("Alian 12WE"));
        System.out.println(replaceAll("ANI1451"));
    }   
}

answered Mar 9, 2013 at 17:32

1218985

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Comments

assylias · Accepted Answer · 2013-03-09 17:11:09Z

2

You could use a regex to remove everyting after a digit is found - something like:

String s = "Alian 12WE";
s = s.replaceAll("\\d+.*", "");

\\d+ finds one or more consecutive digits
.* matches any characters after the digits

answered Mar 9, 2013 at 17:11

assylias

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Comments

Johannes Kuhn · Accepted Answer · 2013-03-09 17:11:47Z

1

Use Regex

"Alian 12WE".split("\\d")[0] // Splits the string at numbers, get the first part.

Or replace "\\d.+$" with ""

answered Mar 9, 2013 at 17:11

Johannes Kuhn

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2 Comments

asifsid88 Over a year ago

Add .trim() to remove trailing spaces

Johannes Kuhn Over a year ago

Look at the example output: Alian

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