How to merge arrays in two objects?

Question

I've got something like:

var object1 = { 'tab1' : [{ test : 10 }, { test : 15 }], 'tab2' : [{ test : 15 }] };

var object2 = { 'tab2' : [{ test : 35 }, { test : 25 }], 'tab3' : [{ test : 40 }] };

And I need the result:

var object3 = { 
    'tab1' : [{ test : 10 }, { test : 15 }],
    'tab2' : [{ test : 35 }, { test : 25 }, { test : 15 }],
    'tab3' : [[{ test : 40 }]
};

How can I do that?

$.extend(true, object1, object2) returns object without { test : 15 } in tab2

the order in tab2 is not random, first should be objects from tab2 object2 and than rest — pucek89
– pucek89, Commented Mar 15, 2013 at 17:36
@howderek he said what he tried: he tried a $.extend call which didn't give him test : 15 in teh results. — Eli Gassert
– Eli Gassert, Commented Mar 15, 2013 at 17:36
You're looking for a deep merge, which jQuery doesn't support. You'll have to do some sort of recursive merge. — robbrit
– robbrit, Commented Mar 15, 2013 at 17:37

hvgotcodes · Accepted Answer · 2013-03-15 17:58:53Z

2

I would just use javascript here, something like

var merged = [];
for (var key in object1) {
    if (object1.hasOwnProperty(key)){
       var obj1Arr, obj2Arr;
       obj1Arr = object1[key];
       obj2Arr = object2[key];

       if (obj1Arr) merged = merged.concat(obj1Arr);
       if (obj2Arr) merged = merged.concat(obj2Arr);
       object3[key] = merged;
        merged = [];
    }
}

for (var key in object2) {
    if (object2.hasOwnProperty(key) && !object3[key]){ // ignore the keys we already found
       var obj1Arr, obj2Arr;
       obj1Arr = object1[key];
       obj2Arr = object2[key];

       if (obj1Arr) merged = merged.concat(obj1Arr);
       if (obj2Arr) merged = merged.concat(obj2Arr);
       object3[key] = merged;
       merged = []; 
    }
}

console.log(object3) and a fiddle

http://jsfiddle.net/H4UGb/1/

you could clean this up a bit by putting the common code in the if statements into a function...

edited Mar 15, 2013 at 17:58

answered Mar 15, 2013 at 17:41

hvgotcodes

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2 Comments

pucek89 Over a year ago

almost great, but remember about that the order in tab2 is not random, first should be objects from tab2 object2 and than rest

hvgotcodes Over a year ago

then switch which array gets merged first

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