Java "String... someStrings" equivalent in PHP

Question

i was wondering if there is a "String...stringArray" equivalent in PHP, something that can build an array based on "stringArray" parameters, i.e.

Java:

public void method1(){
    int aNumber = 4;
    String string1 = "first string";
    String string2 = "second string";
    String string3 = "third string";

    processStrings(aNumber, string1, string2, string3);
    /*
       string1, string2 and string3 will become b = {string1, string2, string3}
       in function "processStrings"
    */
}

public void processStrings(int a, String...b){
    System.out.println(b[0]); //in this case it will print out "first string"
    System.out.println(b[1]); //in this case it will print out "second string"
    System.out.println(b[2]); //in this case it will print out "third string"
}

Is there a way to do the same thing with PHP?

I know i can use

function processStrings($a, $b){}

and then call it like this

function method1(){
    $myInt = 4;
    $strings = array("first string","second string","third string");
    processStrings($myInt, $strings);
}

But i would like to know if there is a way to pass an undefined number of parameters like i do with Java

You have over a thousand reputation. I'm sure you can think of a better title for your question. — Madara's Ghost
– Madara's Ghost, Commented Mar 16, 2013 at 16:04
There is a question related to yours, did you see it? stackoverflow.com/questions/10128477/… — Gökhan Çoban
– Gökhan Çoban, Commented Mar 16, 2013 at 16:11
@GökhanÇoban No i didn't see it, however i need my function to require at least 2 parameters (possibly without having to manually check if func_num_args>=2)... — BackSlash
– BackSlash, Commented Mar 16, 2013 at 16:21

Gökhan Çoban · Accepted Answer · 2013-03-16 16:17:52Z

0

From php manual: func_get_args()

<?php
function foo()
{
    $numargs = func_num_args();
    echo "Number of arguments: $numargs<br />\n";
    if ($numargs >= 2) {
        echo "Second argument is: " . func_get_arg(1) . "<br />\n";
    }
    $arg_list = func_get_args();
    for ($i = 0; $i < $numargs; $i++) {
        echo "Argument $i is: " . $arg_list[$i] . "<br />\n";
    }
}

foo(1, 2, 3);
?>

While you can do it, i offer not to define any arguments in your function, because it gets very confusing when any of the defined arguments are omitted.

answered Mar 16, 2013 at 16:17

Gökhan Çoban

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3 Comments

BackSlash Over a year ago

And what if it is required to have at least 2 parameters? i.e. function1($a,$b [,$c...]) How can i do it (possibly without having to manually check if func_num_args>=2)?

Gökhan Çoban Over a year ago

You can define arguments as i didn't offer in my answer. You should know that func_get_args() will give all of the arguments as array.

Gökhan Çoban Over a year ago

There is no exact equivalent in php like your usage.

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