Split a string into 2 parts in batch

Question

I want to split the name of each folder (in a for loop) into 2 parts : the left part (before the delimiter " - ") and the right part (after the delimiter).

Example : "Bonjour - Cher ami" => left=Bonjour, right=Cher Ami

But it doesn't work :

for /d %%a in (*) do (
  set "fname=%%a" 
  set "right=%fname:* - =%" 
  call set "left=%%fname: - %right%=%%" 
  echo [%left%] * [%right%]
)

Thanks in advance

Do you want to read folder names and split the names and print them? — Illusionist
– Illusionist, Commented Mar 28, 2013 at 23:13

Endoro · Accepted Answer · 2013-03-28 23:44:44Z

1

Inside a code block you need an other syntax:

@echo off &setlocal
for /d %%a in (*) do (
    set "fname=%%~a"
    call set "right=%%fname:* - =%%" 
    call call set "left=%%%%fname: - %%right%%=%%%%"
    call echo [%%left%%] * [%%right%%]
)

If there is no "-" in the folder name, then %left%==%right%.

edited Mar 28, 2013 at 23:44

answered Mar 28, 2013 at 23:24

Endoro

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2 Comments

Basj Over a year ago

Thanks! It works now, except that if %%a = blabla - hehe, then left=blablahehe right=hehe, instead of left=blabla right=hehe

Endoro Over a year ago

Yes, you are right, code needs more %%. Will make an (hopefully last) edit :)

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