Accepting multiple arguments through sh script [UNIX]

Question

What I'm trying to do here is allow users to enter multiple arguments (filenames) and send them to a recycle bin I have created the sh script is called "sh safe_rm"

so I would do this:

$] sh safe_rm testFile2 testFile 3

I need both files able to be passed, any ideas?

file=$1

if [ $# -eq 0 ]
then
   echo "You have not entered a file"
   exit
elif [ -d $file ]
then
   echo "Your file is a directory"
   exit
elif [ -e $file ]
then
   sendToBin
else
   echo "Your file $file does not exist"
   exit


  fi

You'll want to look into this: stackoverflow.com/questions/255898/… — Øyvind Robertsen
– Øyvind Robertsen, Commented Apr 17, 2013 at 17:58

Community · Accepted Answer · 2017-05-23 12:25:17Z

2

Try something like this:

sh safe_rm testFile2 testFile 3

for var in "$@"
do
    echo "$var"
done

This will print:

testFile2
testFile
3

See this post for more info

edited May 23, 2017 at 12:25

CommunityBot

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answered Apr 17, 2013 at 17:59

1337holiday

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1 Comment

glenn jackman Over a year ago

+1. @claybanks, note the necessary use of double quotes everywhere.

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