PHPUnit mock object methods

Question

I am learning unit testing with PHPUnit and am running into a strange problem with mock objects that I can't resolve. I set up these dummy files as an example of what I am experiencing:

Class1

class PrimaryObj1
{
    function doNothing(SecondObj $s)
    {
    }
}

Class2

class PrimaryObj2
{
    function doNothing(SecondObj $s)
    {
        $s->TestMethod();
    }
}

and a test file as:

class PrimaryObj1_test extends PHPUnit_Framework_TestCase
{
    private $primaryObj;
    function setUp()
    {
        $this->primaryObj = new PrimaryObj1();
    }
    function testDoNothing()
    {
        $secondObj = $this->getMock('SecondObj');
        $secondObj->expects($this->once())
                  ->method("TestMethod");
        $this->primaryObj->doNothing($secondObj);
    }
}

(one test file for each dummy class where everything is the same except for the class name).

When I run PHPUnit, this is what I get:

Running Tests/PrimaryObj1_test.php
1) PrimaryObj1_test::testDoNothing
Expectation failed for method name is equal to <string:TestMethod> when invoked 1 time(s).
Method was expected to be called 1 times, actually called 0 times.

Running Tests/PrimaryObj2_test.php
Fatal error: Call to undefined method Mock_SecondObj_99c898e7::TestMethod() in PrimaryObj2.php on line 5

So first it is mad that it didn't call the expected method but then when I do it gets mad cause it is undefined. I just can't win. I think this is why I'm still single...

Any thoughts on why this might be happening?

SecondObj only exists as a Mock. It has no code or class declaration — Aaron Luman
– Aaron Luman, Commented May 1, 2013 at 19:03

Aaron Luman · Accepted Answer · 2013-05-01 19:16:54Z

1

I got a response from an email list serve with the answer. This line:

    $secondObj = $this->getMock('SecondObj');

should be:

    $secondObj = $this->getMock('SecondObj', array('TestMethod'));

Once I made that change it worked as expected.

answered May 1, 2013 at 19:16

Aaron Luman

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