Powershell regex

Question

Is there a Powershell regex command I could use to replace the last consecutive zero in a text string with a "M". For Example:

$Pattern = @("000123456", "012345678", "000000001", "000120000")

Final result:

Thanks.

nhahtdh · Accepted Answer · 2013-05-03 18:16:17Z

6

Search for the following regex:

"^(0*)0"

The regex searches for a consecutive string of 0 at the beginning ^ of the string. It captures all the 0 except the one for replacement. "^0(0*)" also works, since we only need to take note of the number of 0 which we don't touch.

With the replacement string:

'$1M'

Note that $1 is denotes the text captured by the first capturing group, which is (0*) in the regex.

Example by @SegFault:

"000120000" -replace "^(0*)0", '$1M'

edited May 3, 2013 at 18:16

answered May 3, 2013 at 17:59

nhahtdh

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3 Comments

atownson Over a year ago

Would the line read "$Pattern | ForEach-Object {$_ -replace "^(0*)0", "$1M""? Thanks. Sorry, I'm not too familiar with regex, but I thought that would be the way to go.

nhahtdh Over a year ago

@atownson: Sorry, but I am unfamiliar with PowerShell. I know PowerShell uses .NET regex and can write a regex, but I can't write PowerShell command to do it.

Segfault Over a year ago

This answer is good, but use single quotes for the replacement string in powershell. "000120000" -replace "^(0*)0",'$1M' for example.

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