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I want to build a shell script. There should be a conditional flag for CentOS version. I want to set a variable for that version like this

VERSION := $(lsb_release -sr)

But when I included this part I got error. Please someone help me to get the version in shell script.

N.B : lsb_release sr works fine when I give this command in terminal.

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  • 2
    It's uname -r. Why is this tagged c++? Commented May 14, 2013 at 5:24
  • 1
    because I am compiling a C++ code in shell script. Commented May 14, 2013 at 5:28
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    I only need the version like 5.6, 6.3 etc Commented May 14, 2013 at 5:29

2 Answers 2

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In shell script:

VERSION=$(lsb_release -sr) or VERSION=$(/usr/bin/lsb_release -sr) with full path.

will store the release value in $VERSION. What error are you getting ??

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3 Comments

Did you try as said above ??
yup. I have written both suggestions.
Did bash say incorrect ?? what is the output : echo $SHELL
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Try this command

uname -r

-r, --kernel-release     print the kernel release

In my case it is showing only 2.6.39

Or try yourself as uname --help for appropriate choice for you.

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2 Comments

ok thanks... will you write a line, what you should have been done for writing in shell script? my problem is there. I think I am doing wrong in shell script.
i think you are doing right..i am not so good in shell script..just check this or try this

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