Python: Start another python program using parent's python version

Question

I have 2 python programs running - parent program and child program. In my system I have 2 python versions running - 2.7 and 3.3. Sometimes I will use 2.7 to run the program and sometimes I will use 3.3. I will use the following command to run

./parent.py (default python27)
python33 parent.py

How could the parent program call the child run the child program, with the parent's python version?

Thanks in advance

That doesn't make much sense. You would have to be very careful to write a program (or two programs) that would run on both Python 2 and Python 3, as Python 3 made backwards-incompatible changes. — BrenBarn
– BrenBarn, Commented May 27, 2013 at 3:07
Actually my code can support both python27 and python33, as I just use some basic function. Since I need to test the compatibility of the whole system I need to run both program under python27 and python33. Therefore I have this issue which the child running same version as parent. — Winston
– Winston, Commented May 27, 2013 at 3:20
@BrenBarn: using the same source for both Python 2 and Python 3 is a valid choice even non-trivial codebases such as django do it. — jfs
– jfs, Commented May 27, 2013 at 4:32

rh0dium · Accepted Answer · 2013-05-27 13:38:20Z

2

While your example was poor, I think what you are after is sys.executable.

subprocess.call([sys.executable, "manage.py", "celeryd"])

edited May 27, 2013 at 13:38

answered May 27, 2013 at 3:15

rh0dium

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3 Comments

Winston Over a year ago

Thanks a lot. sys.executable is what I need. Thanks

jfs Over a year ago

it is unclear why do you use the string formatting here. If exe is intended as an argument for subprocess functions; a list [sys.executable, "manage.py", "celeryd"] is more portable and safer choice.

rh0dium Over a year ago

Hey J.F. You are are right - I was simply trying to give an example. I updated it to reflect a more clear example.

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