Sorting array by numeric field in an object

Question

I am trying to sort an array of objects by a field that holds numeric value. And this console output is the result of calling:

console.log(_.sortBy( d, 'userid' ));

[Object, Object, Object]
0: Object
count: "6"
name: "Andrey"
userid: "1234"
__proto__: Object
1: Object
count: "9"
name: "Lucas"
userid: "1337"
__proto__: Object
2: Object
count: "30"
name: "M"
userid: "7800"

And it looks fine, just as I expect it to happen.

However when I call this:

console.log(_.sortBy( d, 'count' ));

Instead of seeing array of order count 6, count 9, count 30, I see this:

Array[3]
0: Object
count: "30"
name: "M"
userid: "7800"
__proto__: Object
1: Object
count: "6"
name: "Andrey"
userid: "1234"
__proto__: Object
2: Object
count: "9"
name: "Lucas"
userid: "1337"

Can anyone help me understand what is happening and how can I fix it?

I don't see any numeric values. They're all strings. "9" is different from 9, especially when it comes to comparisons — Ian
– Ian, Commented Jun 5, 2013 at 20:17
And it is sorting it correctly, "30" (the "3") is before "6", which is before "9". — Johan
– Johan, Commented Jun 5, 2013 at 20:19
You got lucky with your sort by userid, in that they're also alphabetically ascending order in addition to numerical ascending order. also put a userid in there with the value of "7" and you'll see what happens. — Eli Gassert
– Eli Gassert, Commented Jun 5, 2013 at 20:20

Jonathan · Accepted Answer · 2013-06-05 20:30:02Z

1

Use parseInt(obj.count) before you sort.

answered Jun 5, 2013 at 20:30

Jonathan

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1 Comment

LucasSeveryn Over a year ago

I used this function when adding elements to my array. Thank you for an useful answer.

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