JSON Parse File Path

Question

I'm stuck trying to get the correct path to the local file. I have the following directories:

Resources ->
   data ->
       file.json
   js ->
     folder ->
        script.js
   html ->
      folder ->
         file1.html

I'm executing script.js from file1.html, with js code:

var answers = JSON.parse('../../data/file.json');
alert(answers);

But it doesn't work, even alert is not starting. What is wrong?

Also I've tried this:

function readJSON(file) {
    var request = new XMLHttpRequest();
    request.open('GET', file, false);
    request.send(null);
    if (request.status == 200)
        return request.responseText;
};

var temp = readJSON('../../data/file.json');
alert(temp);

Alert undefined in this case.

Alert undefined for me., what was the status, did it produce an error in your console? — Paul S.
– Paul S., Commented Jun 7, 2013 at 19:21
Finally, if (request.status == 200) made issues for me. It gives 0 even if it finds the file. If i delete it, all is ok. Thanks for everyone! — jagger
– jagger, Commented Jun 7, 2013 at 19:31

karthikr · Accepted Answer · 2013-06-07 19:32:34Z

60

Since it is in the directory data/, You need to do:

file path is '../../data/file.json'

$.getJSON('../../data/file.json', function(data) {         
    alert(data);
});

Pure JS:

   var request = new XMLHttpRequest();
   request.open("GET", "../../data/file.json", false);
   request.send(null)
   var my_JSON_object = JSON.parse(request.responseText);
   alert (my_JSON_object.result[0]);

edited Jun 7, 2013 at 19:32

answered Jun 7, 2013 at 19:13

karthikr

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7 Comments

Paul S. Over a year ago

I didn't realise you could pass a URI to JSON.parse and have it perform a REQUEST for you, where is this documented?

karthikr Over a year ago

yeah.. edit was on the way.. guess should have answered after the fact

jagger Over a year ago

for your pure js alert is not starting also

Dagrooms Over a year ago

XMLHttpRequest cannot load file:///.../data.json. Cross origin requests are only supported for protocol schemes: http, data, chrome, chrome-extension, https, chrome-extension-resource.

Gaurav Over a year ago

I get this same XMLHttpRequest error when developing locally. Are there any non-network calls to load the local JSON file and parse it for use within client-side JavaScript?

|

O. Jones · Accepted Answer · 2014-05-02 01:26:40Z

10

This solution uses an Asynchronous call. It will likely work better than a synchronous solution.

var request = new XMLHttpRequest();
request.open("GET", "../../data/file.json", false);
request.send(null);
request.onreadystatechange = function() {
  if ( request.readyState === 4 && request.status === 200 ) {
    var my_JSON_object = JSON.parse(request.responseText);
    console.log(my_JSON_object);
  }
}

edited May 2, 2014 at 1:26

O. Jones

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answered May 2, 2014 at 1:04

josephnvu

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4 Comments

O. Jones Over a year ago

Welcome to SO. Good answer. I edited it because it's best when an answer stands alone. Dialogue about other answers is appropriate in comments.

Evorlor Over a year ago

Synchronous XMLHttpRequest on the main thread is deprecated because of its detrimental effects to the end user's experience. For more help, check xhr.spec.whatwg.org.

Todd Over a year ago

@Evorlor Change the false on line 2 to true. Otherwise it's a synchronous operation.

Timo Over a year ago

@Evorlor here is a closer link to what you are writing that one should use async and not sync.

Community · Accepted Answer · 2017-05-23 12:02:20Z

4

Loading local JSON file

Use something like this

$.getJSON("../../data/file.json", function(json) {
    console.log(json); // this will show the info in firebug console 
    alert(json);
});

edited May 23, 2017 at 12:02

CommunityBot

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answered Jun 7, 2013 at 19:27

maazza

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Comments

Sumukh Bhandarkar · Accepted Answer · 2018-12-05 11:07:42Z

3

var request = new XMLHttpRequest();
request.open("GET","<path_to_file>", false);
request.send(null);
var jsonData = JSON.parse(request.responseText);

This code worked for me.

answered Dec 5, 2018 at 11:07

Sumukh Bhandarkar

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1 Comment

Timo Over a year ago

.. but does not work for me, see my comments to the other posts.

Kristaps Karlsons · Accepted Answer · 2013-06-07 19:16:41Z

0

If Resources is the root path, best way to access file.json would be via /data/file.json

answered Jun 7, 2013 at 19:16

Kristaps Karlsons

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1 Comment

jagger Over a year ago

Actually, i make it in titanium webview, so normally resources should be root path. If i make document.location.pathname and start in browser i will for sure get file:/// ...

Miorita · Accepted Answer · 2018-12-24 15:48:20Z

0

My case of working code is:

var request = new XMLHttpRequest();
request.open("GET", "<path_to_file>", false);
request.overrideMimeType("application/json");
request.send(null);
var jsonData = JSON.parse(request.responseText);
console.log(jsonData);

answered Dec 24, 2018 at 15:48

Miorita

3404 silver badges12 bronze badges

1 Comment

Timo Over a year ago

.. but does not work for me, see my comments to the other posts. And .. what is the added value here compared to this? Looks like copy-paste. Welcome to SO.

Der Achim · Accepted Answer · 2021-09-17 08:40:56Z

0

Even if long time answerd, I here is another that does not need to create a request. I created a lg.js script containing a class and some functions (setLg, de, en, ...) Each "lg" function (de, en, fr, ...) provides a json object containing the translations.

"use strict"
class Lg {
  constructor() { this.tr = this.en(); }
  setLg(l) {
    if l == "de" this.tr = this.de(); 
    if l == "en" this.tr = this.en();
  de() {
   "item": "Artikel",
   "login": "Login"
  }
  en() {
   "item": "Item",
   "login": "login"
  }
 }
 var lg = new Lg(); //global accessable object

You can then use it by "lg.tr.item" You could also create a small function, that checks if the "key" is in the JSON object to have some kind of error checking.

answered Sep 17, 2021 at 8:40

Der Achim

907 bronze badges

1 Comment

Timo Over a year ago

This example is too far away from the question I think. An example should be used without any effort and here, I need l var to work with it. Welcome to SO.

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