Dynamic variable echo inside $_POST['']

Question

I have a form that has radio inputs that have a dynamically generated name like below:

<input type="number" name="<?php echo date("Y")-4 ?>brand%gross" placeholder="Gross Sales % for <?php echo date("Y")-4 ?>">
<input type="number" name="<?php echo date("Y")-3 ?>brand%gross" placeholder="Gross Sales % for <?php echo date("Y")-3 ?>">
<input type="number" name="<?php echo date("Y")-2 ?>brand%gross" placeholder="Gross Sales % for <?php echo date("Y")-2 ?>">
<input type="number" name="<?php echo date("Y")-1 ?>brand%gross" placeholder="Gross Sales % for <?php echo date("Y")-1 ?>">

Then the form is processed and creates a dynamic table with all the values the user inputs that is then emailed to me. My question is how do I get dynamically generated radios to output to the table that is sent? I know the below isn't correct but just to give you a better look at what I'm trying to do:

if( isset($_POST) ){
    ${ echo date("Y")-4 } = $_POST['{ echo date("Y")-4 }];

Any help is greatly appreciated!

dynamic table? Do you mean rows created based on the radios selected? — Frederico Schardong
– Frederico Schardong, Commented Jun 7, 2013 at 19:29

Giovanni Di Toro · Accepted Answer · 2013-06-10 14:29:43Z

2

If you want to set a varible content inside $_POST, well... Use a variable.

$foo = date("Y")-4;
$_POST['str'] = $foo;

So... the thing is , you want to use a variable variable name that might go like this:

$foo = date("Y")-4;
$$foo = $_POST[$foo];

Got it?

EDIT 1:

So that the variable won't start with a number:

$bar = "dt_";
$foo = date("Y")-4;
${$bar.$foo} = $_POST[$foo];

edited Jun 10, 2013 at 14:29

answered Jun 7, 2013 at 19:29

Giovanni Di Toro

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8 Comments

Funk Forty Niner Over a year ago

Um, I think you've got a typo in $$foo. ;-)

Giovanni Di Toro Over a year ago

don't think so... It is a double "$", thats why its variable variable, cause its name is variable.

Funk Forty Niner Over a year ago

Hm... interesting. I didn't know that. One learns something new every day.

Giovanni Di Toro Over a year ago

You could use ${$foo} too , I really don't know the difference, but people seem to prefer it.

Funk Forty Niner Over a year ago

Thanks for the additional info. I'll look into that. I remember seeing something related to a similar syntax and there is a purpose, but can't remember off the top of my head right now. Cheers

|

Mike Brant · Accepted Answer · 2013-06-11 22:49:08Z

1

By have a string (the output of date()) from which you subtract and integer, you end up casting the result as an integer, not a string. You are probably better off making the string correctly to begin with and getting rid of the integer arithmetic issue.

I would suggest working with DateTime objects. Here's how you might output you input fields.

<?php
$current_date = new DateTime();
while($i = 1; $i <= 4; $i++) {
    $date_int = new DateInterval('P' . (string)$i . 'Y');
    $temp_date = $current_date->sub($date_int);
    $date_string = $temp_date->format('Y');
?>
    <input type="number" name="<?php echo $date_string; ?>brand%gross" placeholder="Gross Sales % for <?php echo $date_string; ?>" /> 
<?php
} // end while
?>

When processing the $_POST you can do similar:

<?php
$current_date = new DateTime();
$year_array = array();
while($i = 1; $i <= 4; $i++) {
    $date_int = new DateInterval('P' . (string)$i . 'Y');
    $temp_date = $current_date->sub($date_int);
    $date_string = $temp_date->format('Y');
    if (!empty($_POST[$date_string. 'brand%gross'])) {
        $year_array[$date_string] = $_POST[$date_string . 'brand%gross'];
    }
} // end while    
?>

Note that I use an array to store your data indexed by year string , as you can't have a variable name that starts with a number (i.e. $2013nrand%gross is not valid).

I would also STRONGLY suggest using array access notation in your inputs to simply things.

If you made each input like this:

<input type="number" name="year_brand_gross[<?php echo $date_string; ?>]" placeholder="Gross Sales % for <?php echo $date_string; ?>" />

Then the names of year_brand_gross[2013] and such would automatically get populated as an array into $_POST['year_brand_gross'], eliminating the need to loop through the POST input.

Instead you could set this to a variable like this

if(!empty($_POST['year_brand_gross']) {
    $year_array = $_POST['year_brand_gross'];
}

For PHP < 5.3.0 you can use alternate method to generate the year strings:

$current_date = new DateTime();
for ($i = 1; $i <=4; $i++) {
    $current_date->modify('-1 year');
    $date_string = $current_date->format('Y');
    // other code here
}

Note that, as shown, this will alter the value of $current_date with each iteratoin, which differs from the first solution.

edited Jun 11, 2013 at 22:49

answered Jun 7, 2013 at 19:43

Mike Brant

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4 Comments

ItsMIllerTime65 Over a year ago

When trying to implement your example I'm getting an error on the 3rd line of your first block of code.

Mike Brant Over a year ago

What error are you getting? What version of PHP are you using, as DateInterval requires PHP >= 5.3.0?

ItsMIllerTime65 Over a year ago

Just getting a parse error. The version may be the problem... I know I'm running at least 5. I'll have to check and get back to you Monday. Really appreciate the help, Mike!

Mike Brant Over a year ago

@ItsMIllerTime65 I updated the with an alternative approach for PHP < 5.3

Orangepill · Accepted Answer · 2013-06-07 19:37:13Z

0

First off you want to update you html so that the names of the fields

<input type="number" name="year[<?= date("Y")-4 ?>brand%gross]" placeholder="Gross Sales % for <?= date("Y")-4 ?>">
<input type="number" name="year[<?= date("Y")-3 ?>brand%gross]" placeholder="Gross Sales % for <?= date("Y")-3 ?>">
<input type="number" name="year[<?= date("Y")-2 ?>brand%gross]" placeholder="Gross Sales % for <?= date("Y")-2 ?>">
<input type="number" name="year[<?= date("Y")-1 ?>brand%gross]" placeholder="Gross Sales % for <?= date("Y")-1 ?>">

In your PHP you will be able to access the elements by there keys

$val2010 = $_POST["year"]["2010brand%gross"];

answered Jun 7, 2013 at 19:37

Orangepill

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