PHP: A better way of getting the first value in an array if it's present

Question

Here's my code:

$quizId = '';
foreach ($module['QuizListing'] as $quizListing)    {
    if ($quizListing['id']) {
        $quizId = $quizListing['id'];
        break;
    }
}

Is there a better way of doing this?

@baker: $module['QuizListing'] is coming from some SQL query ? — RageZ
– RageZ, Commented Nov 18, 2009 at 9:06

cletus · Accepted Answer · 2009-11-18 09:11:11Z

3

What you're doing is reasonable assuming that:

multiple quiz listings appear; and
not all of them have an ID.

I assume from your question that one of both of these is not true. If you want the first quiz listing then do this:

$listing = reset($module['quizListing']);
$quizId = $listing['id'];

The reset() function returns the first element in the array (or false if there isn't one).

This assumes every quiz listing has an ID. If that's not the case then you can't get much better than what you're doing.

edited Nov 18, 2009 at 9:11

answered Nov 18, 2009 at 9:05

cletus

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Comments

Fenton · Accepted Answer · 2009-11-18 09:12:27Z

1

Slight change:

$quizId = '';
foreach ($module['QuizListing'] as $quizListing)    {
    if (isset($quizListing['id'])) {
        $quizId = $quizListing['id'];
        break;
    }
}

answered Nov 18, 2009 at 9:12

Fenton

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RageZ · Accepted Answer · 2009-11-18 09:13:19Z

1

to answer if this array is coming from a database you probably have to better to filter your query not to include those row at first place

something like

SELECT * from Quiz WHERE id <> 0

this would give you an array usable without any other processing.

answered Nov 18, 2009 at 9:13

RageZ

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Comments

NDM · Accepted Answer · 2009-11-18 09:13:53Z

1

$quiz = array_shift($module['QuizListing']);

if (null != $quiz) {
    echo "let's go";
}

answered Nov 18, 2009 at 9:13

NDM

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1 Comment

Inshallah Over a year ago

Note that array_shift(...) will modify the input array.

TheGrandWazoo · Accepted Answer · 2009-11-18 09:15:03Z

1

Using array_key_exists you can check if the key exists for your array. If it exists, then assign it to whatever you want.

if (array_key_exists('id', $quizListing)) {
  $quizId = $quizListing['id'];   
}

answered Nov 18, 2009 at 9:15

TheGrandWazoo

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