Javascript Replace - Regular Expression

Question

I need to replace a code example: OD3 - The first must always be alpha character, 2nd alphanumeric and the last must always be numeric. What's the regular expression to check and replace the first and regulate the rest to enter correctly? A user could enter in the number 0 instead of the letter O, so I want to correct it immediately...

this is what I have so far: onkeyup="this.value=this.value.replace(/[^a-zA-z]/g,'')

What do you mean by - regulate the rest to enter correctly? — Rohit Jain
– Rohit Jain, Commented Aug 2, 2013 at 11:35
What should happen if it's not correct? Blank out the value? Also how many replacements are there, is it just 0=O ? — MDEV
– MDEV, Commented Aug 2, 2013 at 11:43

amakhrov · Accepted Answer · 2013-08-02 11:42:08Z

1

First, I'd suggest just indicating the error to a user instead of replacing the values. Something like

oninput="if (! /^[a-z][a-z0-9]\d$/i.test(this.value) ) displayMessage('incorrect code');"

If you definitely have to replace the value on the fly, you could do somthing like that:

oninput='validateValue()';
...
function validateValue() {
    var val = this.value;
    if (! /[a-z]/i.test(val[0]) this.value = '';
    else if (! /[a-z0-9]/i.test(val[1]) this.value = val.slice(0,1);
    else if (! /\d/.test(val[2]) this.value = val.slice(0,2);
}

answered Aug 2, 2013 at 11:42

amakhrov

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Comments

Praveen · Accepted Answer · 2013-08-02 11:40:06Z

0

Better have like this.

onkeyup="testRegex(this.value)";

It is not .replace() it is .test()

function testRegex(value) {
   if(value.test(/[^a-zA-z]/g)) {
       alert("Please enter correct value");
       return false;
    }
}

answered Aug 2, 2013 at 11:40

Praveen

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