How to replace string in XSLT?

Question

I have this XML:

<path>/en/products/bike</path>

Is there an XSLT function that will return

/products/bike

?

Thanks for any help.

What are the criteria you want to match on? Do you want the substring starting from the fourth character, the substring following /en, following the second forward slash, the second-to-last slash, etc? There are many ways to extract that particular substring, but some will presumably be more useful to you than others. — Ian Roberts
– Ian Roberts, Commented Sep 8, 2013 at 17:40

Ben L · Accepted Answer · 2013-09-08 17:20:36Z

3

You can use the substring-after function.

So, for example, the following XSLT stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="text"/>

  <xsl:template match="path">
    <xsl:value-of select="substring-after(., '/en')"/>
  </xsl:template>
</xsl:stylesheet>

when applied to your XML:

<path>/en/products/bike</path>

will give:

/products/bike

answered Sep 8, 2013 at 17:20

Ben L

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Mads Hansen · Accepted Answer · 2013-09-08 23:51:06Z

0

With XSLT 2.0 you can also use the replace() function, which accepts a regex pattern as the second parameter and an optional 4th parameter for regex flags.

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="text" />
    <xsl:template match="path">
        <xsl:sequence select="replace(., '^/en','')"/>
    </xsl:template>
</xsl:stylesheet>

answered Sep 8, 2013 at 23:51

Mads Hansen

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