Constructing a multiline string from array in python

Question

I am currently working on a script which sends out the list of defaulters to a distro. I have the values in python list like this ['[email protected]','[email protected]','[email protected]'] I need to form a multiline string from the above array like this

""" 1. [email protected]
    2. [email protected]
    3. [email protected]"""

I tried this

defaultersList = ['[email protected]','[email protected]','[email protected]']  
multilineStr = ""

for item in defaultersList:
  multilineStr = multilineStr + '\n' + item

but out put doesnt come how I expected it to come. Its coming in single line with \n character

Thomas Orozco · Accepted Answer · 2013-09-11 20:54:33Z

1

You are looking for:

"\n".join(["{0}. {1}".format(i+1, person) for i, person in enumerate(defaultersList)])

Of course, the "\n" token will be in the string, but if you call print, you'll see a multiline string.

"\n" is how a newline is represented in Python (and computers in general).

answered Sep 11, 2013 at 20:54

Thomas Orozco

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3 Comments

Krish Over a year ago

I am not printing the string instead it will be email body like this msg = MIMEText("""this is the body of the email""") ... sure \n ill give a new line?

Sven Marnach Over a year ago

Alternative suggestion: "".join(starmap("{0}. {1}\n".format, enumerate(defaultersList, 1))) (with starmap() from itertools).

Krish Over a year ago

I am not printing the string instead it will be email body like this msg = MIMEText("""this is the body of the email""") ... sure \n ill give a new line?

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