PHP function varying parameters

Question

I couldn't find about my issue on google and SO. Hope, i can explain you.

You'll understand when looked following function:

function get_page($identity)
{
    if($identity is id)
       $page = $this->get_page_from_model_by_id($identity);
    elseif($identity is alias)
       $page = $this->get_page_from_model_by_alias($identity);
}

My used function:

get_page(5); // with id
or
get_page('about-us'); // with alias
or
get_page(5, 'about-us'); // with both

I want to send parameter to function id or alias. It should be only one identifier.

I dont want like function get_page($id, $alias)

How can i get and know parameter type with only one variable. Is there any function or it possible?

Are id and alias classes, and the param passed is object of that class? — Lukas Bijaminas
– Lukas Bijaminas, Commented Sep 19, 2013 at 13:56
can't you just call get_page_from_model_by_id and get_page_from_model_by_alias directly? — Otto
– Otto, Commented Sep 19, 2013 at 14:00

Ethan · Accepted Answer · 2013-09-19 14:54:15Z

1

if(is_numeric($identity)) {
    $page = $this->get_page_from_model_by_id($identity);
}
elseif(is_string($identity)) {
    $page = $this->get_page_from_model_by_alias($identity);
}
elseif(func_num_args() === 2) {
    $id = func_get_arg(0);
    $alias = func_get_arg(1);
    //do stuff
}

edited Sep 19, 2013 at 14:54

answered Sep 19, 2013 at 14:00

Ethan

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2 Comments

Bora Over a year ago

I know func_num_args. I was searching function that give me the variable name/type directly. But it's ok. Btw i changed is_int to is_numeric because of i'm getting identity from uri and it's always string.

Ethan Over a year ago

@Bora you should test in the opposite order then, because the number will probably evaluate to true if tested as a string. I edited.

gvm · Accepted Answer · 2013-09-19 14:00:01Z

1

Use is_string() to find whether input is integer or character.

answered Sep 19, 2013 at 14:00

gvm

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Comments

Shankar Narayana Damodaran · Accepted Answer · 2013-09-19 13:58:07Z

0

You should make use of func_get_args()

<?php
function foo()
{
    $numargs = func_num_args();
    echo "Number of arguments: $numargs<br />\n";
    if ($numargs >= 2) {
        echo "Second argument is: " . func_get_arg(1) . "<br />\n";
    }
    $arg_list = func_get_args();
    for ($i = 0; $i < $numargs; $i++) {
        echo "Argument $i is: " . $arg_list[$i] . "<br />\n";
    }
}

foo(1, 2, 3);
?>

Source

answered Sep 19, 2013 at 13:58

Shankar Narayana Damodaran

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Comments

Christoph Diegelmann · Accepted Answer · 2013-09-19 13:58:38Z

0

Here's a complete solution:

function get_page()
{
    $alias = false;
    $id = false;
    foreach(func_get_args() as $arg)
        if(is_string($arg))
             $alias = $arg;
        else if(is_int($arg))
             $id = $arg;

}

answered Sep 19, 2013 at 13:58

Christoph Diegelmann

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Comments

bdf · Accepted Answer · 2013-09-19 14:01:01Z

0

Assuming id is always a number, you could test for it with php's is_numeric()

function get_page($identity)
{
    if(is_numeric($identity) {
       $page = $this->get_page_from_model_by_id($identity);

    } else { 
       $page = $this->get_page_from_model_by_alias($identity);
    }
}

answered Sep 19, 2013 at 14:01

bdf

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