Powershell format operator inside function

Question

I've found out the format operator is working differently inside a function compared to a plain script. Here's a simple example of what is working as expected:

[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
$s = "The {0} thinks that {1}!" -f $name, $statement
write-host $s

producing:

The Scripting Guy thinks that PowerShell rocks!

While inside a function it does something different:

function myFunc( [string] $iname, [string] $istatement) { 
    $s = "The {0} thinks that {1}!" -f $iname, $istatement
    write-host $s
}

[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
myFunc($name, $statement)

produces:

The Scripting Guy PowerShell rocks thinks that !

I tried to play with it to find out what it's doing:

function myFunc( [string] $iname, [string] $istatement) { 
    $s = "The {0} thinks that {1}! {2} {3}" -f $iname, $istatement, "=====", $iname
    write-host $s
}

[string]$name = 'Scripting Guy'
[string]$statement = 'PowerShell rocks'
myFunc($name, $statement)

This produces:

The Scripting Guy PowerShell rocks thinks that ! ===== Scripting Guy PowerShell rocks

So now I don't know what to think about this.

Musaab Al-Okaidi · Accepted Answer · 2013-09-30 15:33:01Z

3

You should call the function as follows:

myFunc -iname "Scripting Guy" -istatement "Powershell Rocks!!"

or

myFunc $name $statement

The current method you're using passes a single array object that's why the elements get printed in succession

answered Sep 30, 2013 at 15:33

Musaab Al-Okaidi

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