Jquery code to find duplicates from an array

Question

i have a json data .

data ={{"id":"10","name":"test"},{"id":"10","name":"test1"},{"id":"11","name":"tsst"},{"id":"41","name":"jhkj"},{"id":"11","name":"yuyyu"},}

from the json data i am fetching the id to get location from a database table as follows

data.each(function( index ) {
    var id = index.id //gets 10
                       //again gets 10 and again doing db operations for same id value 
    //db operations 
      //get location details from db using this id    
    // operations after getting locations....................

    });

my proble is id is repeated ie 10,10,11,41 ,11.so calling db operations for repeated values also.How can i avoid by calling db operations for repeated id values .

Arun P Johny · Accepted Answer · 2013-10-02 06:34:29Z

3

Try

var temp = {};
for(var i = 0; i < data.length ; i++ ){
    var obj = data[i];
    if(temp[obj.id] >= 0){
        data.splice(i, 1);
        i--;
    }
    temp[obj.id] = i;
}
console.log(data)

Demo: Fiddle

answered Oct 2, 2013 at 6:34

Arun P Johny

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Comments

4b0 · Accepted Answer · 2013-10-02 06:38:27Z

2

Check for duplicate ID may solve your problem.

For Example:

var dup= {};
data.each(function( index ) {
    var id = index.id;
    dup.push(id);
    if (dup[id])
        $(this).remove(); //OR DO nothing
    else
     //Your DB Operation

});

edited Oct 2, 2013 at 6:38

answered Oct 2, 2013 at 6:29

4b0

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1 Comment

stUrb Over a year ago

You forget to add the tested ID's from data to the dup array.

Alex · Accepted Answer · 2013-10-02 06:29:38Z

0

I think you have to avoid to call DB operations for all id in the loop. Just pass everything to backend and get data for all id which you need within one DB operation.

answered Oct 2, 2013 at 6:29

Alex

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Comments

Sunil Verma · Accepted Answer · 2013-10-02 06:30:52Z

0

Create another array and add the value in it after checking that it exists or not.

you can use inArray ref : http://api.jquery.com/jQuery.inArray/ for this purpose.

answered Oct 2, 2013 at 6:30

Sunil Verma

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