call a function from one file in node.js

Question

i have a file named test2.js created a function inside it

var schedule = require('node-schedule');   
var jobScedule = function(time, jobid) {
  schedule.scheduleJob(time, function(jobid){

console.log("scheduling starts");
});

}
exports.jobScedule = jobScedule;

in test1.js i have to call this function.

var objTest2 = require("./Test2.js");
var time = new Date();
var jobid=10;
objTest.jobScedule(time,jobid)

console.log(time);
console.log(jobid);

i dont know to call function from another file in node.js.rectify me

I think the filename for the require is case sensitive. Check your case and spelling. Also, try removing the leading ./ in the require if everything is in the same directory. — user949300
– user949300, Commented Nov 1, 2013 at 6:56
Possible duplicate of In Node.js, how do I "include" functions from my other files? — Towerss
– Towerss, Commented Sep 5, 2017 at 4:24

divz · Accepted Answer · 2013-11-07 03:44:16Z

4

var objTest= require("./Test2.js");

    var time = new Date();
    var jobid=10;
    objTest.jobScedule(time,jobid)

    console.log(time);
    console.log(jobid);

answered Nov 7, 2013 at 3:44

divz

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Comments

Nija I Pillai · Accepted Answer · 2019-11-06 08:42:03Z

2

In 'user.js', contains functions to be exported like

module.exports = {
  func1: function () {
    // func1 
  },
  func2: function () {
    // func2 
  }
};

In the other admin.js files, you can include the 'user.js' by

const user = require('./user');

In the following code, the exported funct1 can be like

user.func1();

answered Nov 6, 2019 at 8:42

Nija I Pillai

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