Looping through an array with PHP

Question

I want to use PHP to populate an array starting with today's date and going several days into the future. When I tried the following below all of the columns contain "2013-11-18." I have been toying with it for 2 hours, but to no avail. What am I missing?

//Get "Day 0", today if undefined
if(isset($_GET['DAY0']) == TRUE){
    $day0 = new DateTime($_GET['DAY0']);
} else {
    $day0 = new DateTime('today');
}

    // save day0 + 7 days into into dayArray
    $dayArray[0] = $day0;
    for($i=1; $i<8; $i++){
        $day0->modify('+1 day');
        $dayArray[i]= $day0;
    }

    echo "<tr>"; 
    for ($i = 0; $i < 7; $i++) {
        echo "<th>".$dayArray[i]->format('Y-m-d')."</th>";
    }
    echo "</tr>";

Rob · Accepted Answer · 2013-11-11 16:20:31Z

2

Objects are passed by reference. You are assigning multiple references to the same object in your array.

If you really need all the datetime objects in the array, you could do something like this

$interval = new DateInterval('P1D');
$start = new DateTime('today');

$dayArray = [clone $start];

for ($i = 1; $i < 8; $i++) {
    $dayArray[] = clone $start->add($interval);
}

Or you could just store the formatted dates as already suggested.

$interval = new DateInterval('P1D');
$start = new DateTime('today');

$dayArray = [$start->format('Y-m-d')];

for ($i = 1; $i < 8; $i++) {
    $dayArray[] = $start->add($interval)->format('Y-m-d');
}

edited Nov 11, 2013 at 16:20

answered Nov 11, 2013 at 15:23

Rob

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3 Comments

Ishikawa Over a year ago

Could you please tell me how to do that because I can't figure it out... sorry

Mihai Iorga Over a year ago

@Rob, $dayArray = [clone $start]; is not ok, what language? $dayArray = [$start->format('Y-m-d')]; also not ok. What's with [ and ] on both of them?

Rob Over a year ago

That is short array syntax added in php 5.4.

rink.attendant.6 · Accepted Answer · 2013-11-11 15:24:18Z

0

Replace two of your $dayArray[i] with $dayArray[$i]

edited Nov 11, 2013 at 15:24

rink.attendant.6

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answered Nov 11, 2013 at 15:22

Paul Lo

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2 Comments

Ishikawa Over a year ago

I tried that and it produced a fatal error... I think because of the format thing.

Paul Lo Over a year ago

Oh ya, the major problem is in @Rob's answer, but this one should also be corrected.

Mihai Iorga · Accepted Answer · 2013-11-11 15:33:09Z

0

You could save timestamps:

// save day0 + 7 days into into dayArray
$dayArray[0] = $day0->format('U');
for($i=1; $i<8; $i++){
    $day0->modify('+1 day');
    $dayArray[$i] = $day0->format('U');
}

echo "<tr>"; 
for ($i = 0; $i < 7; $i++) {
    echo "<th>".date('Y-m-d', $dayArray[$i])."</th>";
}

answered Nov 11, 2013 at 15:33

Mihai Iorga

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Comments

Tom · Accepted Answer · 2013-11-11 15:50:10Z

0

You can create a DatePeriod like so:

    if(isset($_GET['DAY0']) == TRUE){
        $day0 = new DateTime($_GET['DAY0']);
    } else {
        $day0 = new DateTime('today');
    }

    $enddate = new DateTime();

    $period = new DatePeriod(
            $day0,
            new DateInterval('P1D'),
            $enddate->add(new DateInterval('P7D'))
    );

    echo "<tr>";
      foreach ($period as $datetime) {
         echo "<th>".datetime->format('Y-m-d')."</th>";

      }
    echo "</tr>";

answered Nov 11, 2013 at 15:50

Tom

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2 Comments

Ishikawa Over a year ago

Thanks for your answer, but I wanted to store each date in an array because I loop through them a second time to populate the table...

Tom Over a year ago

You can use iterator_to_array() function to convert the period into an array.

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