How to get integer from list and construct hash table in Python?

Question

New to python. I have a tuple variable containing some information and i convert it into list. When I print each data element out by using my for loop, I got.

for data in myTuple:
    print list(data)

['1', " This is the system 1 (It has been tested)."]
['2', ' Tulip Database.']
['3', ' Primary database.']
['4', " Fourth database."]
['5', " Munic database."]
['6', ' Test database.']
['7', ' Final database.']

The problem is how I get the the number (which is in single quote/double quotes) and store it in a dictionary as below:

{’1’: 'This is the system 1 (It has been tested).', ’2’: 'Tulip Database.', ...}

Thank you.

The keys in this case will be strings unless converted - maybe they should be numbers? — user2864740
– user2864740, Commented Nov 24, 2013 at 19:49

shad0w_wa1k3r · Accepted Answer · 2013-11-24 19:50:24Z

1

As pointed out by JBernardo, you could use the builtin dict().

You can also use a dictionary comprehension!

myTuple = [['1', " This is the system 1 (It has been tested)."],
           ['2', ' Tulip Database.']]
print {key:value for key, value in myTuple}

Output

{'1': ' This is the system 1 (It has been tested).', '2': ' Tulip Database.'}

answered Nov 24, 2013 at 19:50

shad0w_wa1k3r

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Comments

Ashwini Chaudhary · Accepted Answer · 2013-11-24 19:51:08Z

1

Use dict():

my_dict = dict(myTuple)

Demo:

>>> x = ([1, 'spam'], [2, 'foobar'])
>>> dict(x)
{1: 'spam', 2: 'foobar'}

dict() when passed an iterable does something like this(from help(dict)) :

dict(iterable) -> new dictionary initialized as if via:
    d = {}
    for k, v in iterable:
        d[k] = v

edited Nov 24, 2013 at 19:51

answered Nov 24, 2013 at 19:45

Ashwini Chaudhary

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1 Comment

JBernardo Over a year ago

why? If data is iterable, there's no need to do this

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