I am getting this as var_dump:
array(1) {
[0]=>
array(4) {
["num"]=>
string(1) "1"
["yyyy"]=>
string(4) "2013"
["mm"]=>
string(2) "12"
["dd"]=>
string(2) "11"
}
}
How to access the array elements?
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I am using fetch mode as ASSOC, so why am I still getting array within another array? Newbie here, pardon for noviceness :)pk10– pk102013-11-27 10:54:06 +00:00Commented Nov 27, 2013 at 10:54
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$array_variablename[index]Zahidul Hossein Ripon– Zahidul Hossein Ripon2013-11-27 10:54:19 +00:00Commented Nov 27, 2013 at 10:54
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use foreach to iteraterakimo– rakimo2013-11-27 10:54:53 +00:00Commented Nov 27, 2013 at 10:54
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@user2961121: you are probably getting multiple rows from your db. But since it's only one row, it has the index. If you were to select more rows it should be clear.knittl– knittl2013-11-27 10:57:51 +00:00Commented Nov 27, 2013 at 10:57
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Perhaps you should read up on PHP arrays: us2.php.net/manual/en/language.types.array.phpGeorge– George2013-11-27 10:59:56 +00:00Commented Nov 27, 2013 at 10:59
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6 Answers
Let's assume your array is $arr, you can do
echo $arr[0]['num'];
echo $arr[0]['yyyy'];
echo $arr[0]['mm'];
echo $arr[0]['dd'];
As you are fetching from a database, you will receive an array for each result row, and within each array will be another array of columns. you can use a foreach() loop to iterate over the data, as follows:
foreach($arr as $row) {
echo $row['num'] . ':' . $row['yyyy'] . '-' . $row['mm'] . '-' . $row['dd'] . "\n";
}
Comments
try this
foreach($array as $value) {
foreach($value as $k=>$v) {
echo $k . " : " . $v .'<br/>';
}
echo '<hr>';
}
Comments
Please have a look at the official PHP Doc article about arrays.
In your case:
$yourArrayVariable[0]['yyyy']
Will let you access the element with value 2013.
Or if you have an undefined number of array entries you can iterate over it with either foreach or for.
foreach($yourArrayVariable as $key => $value) {
echo $key , ': ' , $value , '<br>';
}
or if you have only numeric indeces without a gap:
$arrCount = count($yourArrayVariable);
for($i = 0; $i < $arrCount; ++$i) {
echo $i , ': ' , $arrCount[0] , '<br>';
}
Comments
store array in a variable like
$arr =array(1) {
[0]=>
array(4) {
["num"]=>
string(1) "1"
["yyyy"]=>
string(4) "2013"
["mm"]=>
string(2) "12"
["dd"]=>
string(2) "11"
}
}
for access array elements you have to use following code
echo $arr[0]['num'];
echo $arr[0]['yyyy'];
echo $arr[0]['mm'];
echo $arr[0]['dd'];o $arr[0]['num']
1 Comment
Chris Wheeler
Did you just copy and paste my answer?
$arr =Array(
0=>array(
"num"=>"1",
"yyyy"=>"2013",
"mm"=>"12",
"dd"=>"11",
)
);
foreach ($arr as $value) {
echo "num: ".$value["num"];
echo "yyyy: ".$value["yyyy"];
echo "mm: ".$value["mm"];
echo "dd: ".$value["dd"];
}
Comments
You can get the value using echo $array[0]['num']; gives output as 1
$array ='your array data here';
foreach($array as $key=>$value) {
echo "num: ". $value['num'] . "/yyyy: ". $value['yyyy']. " /mm: ". $value['mm'] . " /dd: ". $value['dd'] . "<br>";
}
3 Comments
Vijay
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post.
Krish R
@win, why not, how you said that. run this code will give output.
Krish R
@win com'on buddy, just look at unaccepted answer as well. All the answers are not same, If could, even you can post better then all.