why is this not producing the expected array of results
IFS=$'\n'; read -a list <<< `lsblk` ; echo ${list[*]};
Because I need to add to this question I have to say that I am a bit confused as to why
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2 Answers
Maybe you're looking for this:
IFS=$'\n'; readarray list < <(lsblk)
And maybe it's better to check the result this way:
for i in ${list[@]}; do echo $i; done
The <(lsblk) there is called process substitution, you can read about it in the Process Substitution section of man bash.
On systems without readarray, you could do like this instead:
IFS=$'\n'; while read line; do list+=($line); done < <(lsblk)
1 Comment
James
readarray though works is not on the bsd machines i need it to be on = /
Probably you need to use -l flag to get a list of devices, because by default lsblk output is in some tree view. (I don't have lsblk, but with lsusb I have expected result):
IFS=$'\n'; read -a list <<< `lsblk -l` ; echo ${list[*]};
You can also try the more native way of array creation below:
list=( $(lsblk -l) ); echo ${list[*]}
4 Comments
pmod
@JamesAndino Then, what means "not producing" ?
James
an array of all block devices recognized by the system
James
No the output of that echo with no quotes though looses information would still produce an output I can tell its working from as opposed to the out put of my command thats wronger then the just wrong input of my poor echo
pmod
@JamesAndino Isn't it that lsblk produces by default output in some tree format, maybe you wanted list?