Bash not evaluating variable name properly

Question

I changed directory name of my log file to include $$ (pid) of the bash script. If I add $$ to the directory name, the following expression fails to execute.

command $@ >> $log 2>> $log;

#Initial line that works 
log="$work/$1";

#Modified with $$ - didn't work
log="$work/$$/$1";

Does the $work/$$ directory exist before you run that?

Mat
– Mat

2013-12-08 07:10:16 +00:00
Commented Dec 8, 2013 at 7:10 — Mat
– Mat, Commented Dec 8, 2013 at 7:10

John1024 · Accepted Answer · 2013-12-08 07:21:33Z

1

"didn't work" is a vague description of the problem. One issue that I spot is that generally one cannot write to a directory that does not yet exist. mkdir would solve this:

log="$work/$$/$1"
mkdir -p "$work/$$"
command $@ >>$log 2>>$log

answered Dec 8, 2013 at 7:21

John1024

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