Object oriented php class simple example

Question

i am beginner on php so now i try to learn object oriented i was goggling i got it some ideas but not clear concept.So i come there.Please any php guru give simple example of how to crate classes and how to call on other php page.

for example

i want two classes one is show name and second one is enter name.First class show name this name come from database and second class put name in database.

Index.php

<form action="checking.php" method="post">
      <input type="text" placeholder="Please enter name">
</form>

you do not need two class for that all you need is two method one for adding data and other is for fetching data from database.. — Dipesh Parmar
– Dipesh Parmar, Commented Dec 16, 2013 at 5:25
@DipeshParmar yes you right i need one class thanks for suggestion. — Affan Ahmad
– Affan Ahmad, Commented Dec 16, 2013 at 6:37

Veer Shrivastav · Accepted Answer · 2014-10-03 18:52:30Z

14

The way you are calling a php page is good. That is from HTML.

What I think, you are getting this wrong. A class showName to get name from database and enterName to save in database. Well what I suggest that should be a function within one single class.

<?php
class Name
{
    public $name;
    public function showName()
    {
        /**
        Put your database code here to extract from database.
        **/
        return($this->name);
    }
    public function enterName($TName)
    {
        $this->name = $TName;
        /**
        Put your database code here.
        **/
    }
}
?>

In checking.php you can include:

<?php
    include_once("name_class.php");
    $name = $_POST['name'];   //add name attribute to input tag in HTML
    $myName = new Name();
    $myName->enterName($name); //to save in database/
    $name=$myName->showName(); //to retrieve from database. 
?>

This way you can achieve this, this is just an overview. It is much more than that.

edited Oct 3, 2014 at 18:52

answered Dec 16, 2013 at 5:40

Veer Shrivastav

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1 Comment

RPDeshaies Over a year ago

I think there's an error in your code. You can't put the $ after a $this-> because it will throw a PHP exception. See line this->$name = $TName;

Balaji Perumal · Accepted Answer · 2013-12-16 05:29:22Z

4

You have to create a class person and two methods..

class Person{
    public $name;
        public function showName()
        {
             echo $this->name;
        }

        public function enterName()
        {
             //insert name into database
        }
}

answered Dec 16, 2013 at 5:29

Balaji Perumal

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2 Comments

Mischa Over a year ago

You should not "echo" from within a method. Just "return" and let the user of this class decide what he want to do with the given data.

Balaji Perumal Over a year ago

@MischaBehrend, return is good. But this method is not getName(). For getting/setting getter/setter will be good.. Anyway thanks for your interest in this answer after two years though.

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