I have the user input a string A for example "sun is clear". I have a string B in the database "sun cloud rain". How would I detect if part of String A is part of String B?
I used @sky.include?(activity.sky) where @sky is String A and activity.sky is String B. This works only when String A is sun.
You can split the strings into two arrays
a = "sun is clear".split
b = "sun cloud rain".split
and compute the intersection
a & b
# => ["sun"]
(a & b).empty?
# => false
If the intersection is not empty, then they share pieces. Otherwise, you can also compute the difference of a - b
(a - b).size == a.size
# => false
(a & b).empty?
To match a word of String A a is a one of words of String B use the following:
activity.sky.split( /\s+/ ).any? {|s| @sky.include?(s) }
split and then put & operator
(@sky.split(" ") & activity.sky.split(" ")).empty?
If neither A nor B itself includes a duplicate of words, then you can check like this:
A = "sun is clear"
B = "sun cloud rain"
"#{A} #{B}" =~ /\b(\w+)\b.*\b\1\b/ # => 0 (non-nil means there is a common word)
A = "sun is clear"
B = "cloud rain"
"#{A} #{B}" =~ /\b(\w+)\b.*\b\1\b/ # => nil (nil means there is no common word)
Otherwise, you can insert some non-letter non-space character (e.g., "|") between the two strings:
A = "sun is sun"
B = "sun cloud rain"
"#{A}|#{B}" =~ /\b(\w+)\b.*|.*\b\1\b/ # => 0
A = "sun is sun"
B = "cloud rain"
"#{A}|#{B}" =~ /\b(\w+)\b.*|.*\b\1\b/ # => nil
String Aa is a one of words ofString B?AandB, a part ofAis always a part ofB. Proof: The empty string is part ofAand is also a part ofB.