Ajax call in Javascript

Question

I want to get value in JavaScript using Ajax Call,
I am using the following code:

var value = $.ajax({
    type:"GET",
    url:"get_result.php",
    data:"{'abc':" + $abc + "}",
});

alert(value);

while I wrote following code in get_reult.php:

<?php
    echo $abc= "Working";
?>

Happy to know about good solution

Have a look at the jQuery tutorial to learn how to make Ajax calls with jQuery and process the response with the server: learn.jquery.com/ajax. The purpose of this tutorial is to help developers in exactly your situation. — Felix Kling
– Felix Kling, Commented Dec 26, 2013 at 8:13

Nanhe Kumar · Accepted Answer · 2013-12-26 08:15:08Z

1

$.ajax({
  url: 'get_result.php',
  type: 'GET',
  data: 'abc='+$abc,
  success: function(data) {
    //called when successful
    alert(data);
  },
  error: function(e) {
    //called when there is an error
    //console.log(e.message);
  }
});

answered Dec 26, 2013 at 8:15

Nanhe Kumar

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Comments

Elad Stern · Accepted Answer · 2013-12-26 08:14:42Z

0

You're looking for the success parameter in your call:

<script>
$.ajax({
    type:"GET",
    url:"get_result.php",
    data:"{'abc':" + $abc + "}",
    success: function(result) {
        alert(result);
    }
});
</script>

Read more about AJAX calls with jQueryhere

answered Dec 26, 2013 at 8:14

Elad Stern

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Comments

Scary Wombat · Accepted Answer · 2013-12-26 08:15:54Z

0

The ajax call is asynchronous so that the result is probably not available when you call alert(value);

You will need to put this code into a success block.

$.ajax({
    type:"GET",
    url:"get_result.php",
    data:"{'abc':" + $abc + "}"
}).success (function(value) 
{
  alert(value);
});

answered Dec 26, 2013 at 8:15

Scary Wombat

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