The code shown below:
for count in range(0, 5):
print(count)
The output will be:
0 1 2 3 4
The question is Is it possible to iterate in Python out of order:
Something like this:
for count in range(5, 0):
print(count)
the output: 4 3 2 1 0
range(start, stop[, step])
It accepts the third parameter step
So you can do this way:
for count in range(4, -1, -1):
print(count)
range returns a list of integers in python3? Really?This answer will help:
for x in reversed(range(5)):
print x
You can use reversed() to inverse the order of values in iterator:
for x in reversed(range(5)):
print x
import random
l = range(0, 5)
random.shuffle(l)
for count in l
print count
RANGE produces APs(Arithmetic Progressions).
In this case the step size is negative.
You can specify step size by:
range(Start of series, End of series [, Step size])
Thus here we use:
for counter in range(4, -1, -1):
print counter
End of series is always 1*(step size) less than the value passed to range.
NOTE:
reversed(range(...))
Can also be used, but its efficiency is lower compared to the above method.
Additionally many other manipulation functions do not work with reversed() yet.
reversed(range(0,5)). source: [stackoverflow.com/questions/7286365/… [1]: stackoverflow.com/questions/7286365/…