Alternative to eval() for an array of bitwise operation on an array

Question

I have an array that I want to use with the the bitwise inclusive or operation.

The two solutions at the moment are:

A foreach() loop that evaluates them in order

$final = 0;
foreach($bits as $bit)
  $final = $final | $bit;
}

Imploding the array with the bitwise OR as the glue, and eval() the string

eval(implode(' | ', $bits));

Are these the only options or am I missing a simple native array method?

Check if there is atleast one 1 in the array. If there is, then the output is 1, else 0 :P — HamZa
– HamZa, Commented Jan 4, 2014 at 23:25
If the $bits are already exclusive, then array_sum would do. — mario
– mario, Commented Jan 4, 2014 at 23:27
@HamZa, sorry, to clarify this is used before a following & check against another value, so I need more than a boolean response. Thanks — Rhys
– Rhys, Commented Jan 5, 2014 at 0:29
@mario Of course, thank you. array_sum with array_unique does it! — Rhys
– Rhys, Commented Jan 5, 2014 at 0:31
@HamZa the resulting value is required for another bitwise operation afterwards, so I required a combination of the array's bits — Rhys
– Rhys, Commented Jan 5, 2014 at 0:33

Rhys · Accepted Answer · 2014-01-05 00:32:37Z

2

Following @mario's comment, the solution is:

array_sum(array_unique($bits));

answered Jan 5, 2014 at 0:32

Rhys

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