Find specific string with jquery

Question

I use a 'change'-function to put the value of selectbox into an input

$("#afa_select").change(function() {
    var nd_value = $('#afa_select :selected').text();
    $("#nd_hidden").val(nd_value);
});

The options of the selectbox contain the following strings:

text 10 Jahre
another text 6 Jahre
just another text 12 Jahre
another text with a figure e.g. 1000 6 Jahre
another text with a figure e.g. 3234 6 Jahre

I need to find the number in front of the string " Jahre" and put this value into the input #nd_hidden.

This isn't a jQuery thing, it's a JavaScript thing. What have you tried? Where are you getting stuck? — T.J. Crowder
– T.J. Crowder, Commented Jan 7, 2014 at 15:43
Can you use that number as the attribute for the options, it would be easier to read that way, just a suggestion. Other way is to do it with regex. — Mutant
– Mutant, Commented Jan 7, 2014 at 15:43
If 'Jahre' always going to be there you can simply do - nd_value[nd_value.length-7], but I would still do it regex way — Mutant
– Mutant, Commented Jan 7, 2014 at 15:46

T.J. Crowder · Accepted Answer · 2014-01-07 15:44:37Z

5

This is trivial with a regular expression:

var text = "another text with a figure e.g. 1000 6 Jahre";
var result = /(\d+) +Jahre/.exec(text);
if (result) {
    console.log(result[1]); // "6"
}

If you need it as a number:

var num = parseInt(result[1], 10);

The regular expression says: "Find the first match in the string that's a series of digits followed by one or more spaces followed by the characters Jahre and capture the digits in a capture group." result will be null if no match was found. If a match is found, the contents of the first capture group are in result[1].

answered Jan 7, 2014 at 15:44

T.J. Crowder

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Comments

Brad · Accepted Answer · 2014-01-07 15:46:16Z

2

you could also split the string on a space and get the n-2 position if you don't want to use regular expressions.

var selectNumber = nd_value.split(" "); 
var yourNumber = selectNumber[selectNumber.length-2]; 

console.log(yourNumber);

answered Jan 7, 2014 at 15:46

Brad

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