PHP isn't getting a variable from form

Question

Hi guys I have a simple form that will allow users to sign up

  <form name="signupform" id="signupform" onsubmit="return false;">
    <div>Username: </div>
    <input id="username" type="text" onblur="checkusername()" onkeyup="restrict('username')" maxlength="16">
    <span id="unamestatus"></span>
    <div>Email Address:</div>
    <input id="email" type="text" onfocus="emptyElement('status')" onkeyup="restrict('email')" maxlength="88">
    <div>Create Password:</div>
    <input id="pass1" type="password" onfocus="emptyElement('status')" maxlength="16">
    <div>Confirm Password:</div>
    <input id="pass2" type="password" onfocus="emptyElement('status')" maxlength="16">
    <div>Unique Company ID:</div>
    <input id="companyID" type="number" onfocus="emptyElement('status')">
    <div>Company Name:</div>
    <input id="compname" type="text" onfocus="emptyElement('status')">
    <button id="signupbtn" onclick="signup()">Create Account</button>
    <span id="status"></span>
  </form>

However, i'm getting a problem in that one of the form parts, the company name is not being commited to a variable, I know this because I check it with the following code in ajax.

if(u == "" || e == "" || p1 == "" || p2 == "" || c == "" || cid == "" || cn == ""){
status.innerHTML = "Fill out all of the form data";

now, the weird thing is I'm sure that I am saving the variables correctly. The form should call the following ajax function.

function signup(){
var u = _("username").value;
var e = _("email").value;
var p1 = _("pass1").value;
var p2 = _("pass2").value;
var cid = _("companyID").value;
var cn = _("compname").value;
var status = _("status");

and then it gets sent with
ajax.send("u="+u+"&e="+e+"&p="+p1+"&c="+c+"&cid="+cid+"&cn"+cn);

and in the php I have it so I assign it to variables in php

// GATHER THE POSTED DATA INTO LOCAL VARIABLES
$u = preg_replace('#[^a-z0-9]#i', '', $_POST['u']);
$e = mysqli_real_escape_string($db_conx, $_POST['e']);
$p = $_POST['p'];
$cid = preg_replace('#[^0-9]#', '', $_POST['cid']);
$cn = preg_replace('#[^a-z0-9.\- ]#', '', $_POST['cn']);
$c = preg_replace('#[^a-z ]#i', '', $_POST['c']);

but it keeps running into that else if, and even when I remove that, no data gets commited to the database for compname ($cn) ONLY, every other variable gets send and stored in the database except for $cn.

Was wondering if I've done something fundamentally wrong here, or its just i've missed something out?

Thanks in advance!

EDIT - changes question to deal with new issue that has arisen.

Probably just your typo: +"$cn"+cn should be +"&cn"+cn. Although you probably should url encode your values as well. — jeroen
– jeroen, Commented Jan 16, 2014 at 21:17
after that is changed this code is getting thrown up status.innerHTML = "Fill out all of the form data"; which is directly after I declare my vars in ajax, where is passes through a check to see if any of the fields are empty. — Duenna
– Duenna, Commented Jan 16, 2014 at 21:20

Ben Siver · Accepted Answer · 2014-01-16 21:17:46Z

3

The issue is with your AJAX call:

ajax.send("u="+u+"&e="+e+"&p="+p1+"&c="+c+"&cid="+cid+"$cn"+cn);

should be

ajax.send("u="+u+"&e="+e+"&p="+p1+"&c="+c+"&cid="+cid+"&cn="+cn);

answered Jan 16, 2014 at 21:17

Ben Siver

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1 Comment

Duenna Over a year ago

after that gets changed ajax is now telling me "Fill out all the form data" which is related to a check to see if any of the fields are empty.

hemanth · Accepted Answer · 2014-01-16 22:55:10Z

0

If condition has variable c and your are not setting value for variable c in your signup function.

hope this helps.

answered Jan 16, 2014 at 22:55

hemanth

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