Conversion of string array into another string array on the basis of a parameter

Question

I have another question.

How to convert a string array to another string array on the basis of a parameter?

string[] x={ "A", "B", "C", "D", "E", "F", "G" };
string[] y=new string[number];

for(int I=0;i<number;i++)
{
y=x[i];
}

The above implementation shows error.

If the parameter number is 3, then array y should have A,B,C,D.

Basically on the basis of a parameter, I want to generate another array from the parent array

I know this question is not too high-tech but I am not able to get around it.

Help will be greatly appreciated.

Regards

Anurag

Soner Gönül · Accepted Answer · 2014-01-17 13:10:01Z

4

Array.Copy has an overload called Array.Copy Method (Array, Array, Int32)

Copies a range of elements from an Array starting at the first element and pastes them into another Array starting at the first element.

Array.Copy(x, y, number + 1);

For a full example;

string[] x = { "A", "B", "C", "D", "E", "F", "G" };
string[] y = new string[4];
Array.Copy(x, y, 4);
foreach (var item in y)
{
    Console.WriteLine(item);
}

Output will be;

A
B
C
D

Here a demonstration.

edited Jan 17, 2014 at 13:10

answered Jan 17, 2014 at 12:59

Soner Gönül

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1 Comment

Anurag Over a year ago

Thank you..i didn't know about Array.Copy method.

CodingIntrigue · Accepted Answer · 2014-01-17 12:59:45Z

2

It shows an error because you have declared int I, but tried to access i and also, you need to access y using an indexer:

string[] x={ "A", "B", "C", "D", "E", "F", "G" };
string[] y=new string[number];

for(int i=0;i<number;i++)
{
    y[i] = x[i];
}

Will work fine, however you may need to increment number by one if you want number to be 3 yet store the first 4 values...

answered Jan 17, 2014 at 12:59

CodingIntrigue

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1 Comment

Anurag Over a year ago

Thank you Mr.Graham..Now I get it..it wasn't a case of case-sensitivity. I was not using 'i' as an index parameter when accessing y. Silly me...

Selman Genç · Accepted Answer · 2014-01-17 12:59:08Z

2

There is no need to for loop. You can do it with LINQ

string[] y = x.Select(item => item).Take(number+1).ToArray();

answered Jan 17, 2014 at 12:59

Selman Genç

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4 Comments

Cosmin Vană Over a year ago

This is not the most efficient method. However, it has the advantage that you don't need to care about number+1 being bigger then x size.

Selman Genç Over a year ago

@Cosmin, OP didn't say anything about that.If that is the case the for loop might be throw exception too.He should check number

Anurag Over a year ago

Thank you...I will try the solution

Cosmin Vană Over a year ago

That's what I'm saying. By using Take you won't get that exception. You will just get a smaller array so you should no longer be concerned about the check.

TomT · Accepted Answer · 2014-01-17 13:06:18Z

0

First you need a bigger array if number=3 should give you A,B,C,D

string[] x={ "A", "B", "C", "D", "E", "F", "G" };
string[] y=new string[number+1];

And use Array.Copy to copy the elements

Array.Copy(x, y, number+1);

answered Jan 17, 2014 at 13:06

TomT

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