jQuery output after php check

Question

Hi again here to ask you for a problem solved in first part on my first question. i've a form that submit data via jQuery to a php page, the code:

var messaggio = $("input[name='messaggio']").val();
$.ajax({
   url:"js/php/sendchat.php",
   data:"messaggio="+messaggio,
   type:"post",
   success:function(data){
      $("input[name='messaggio']").val("");
      $("body").html(data);
   }
});

When i check send via jQuery, there's no output, and I still cannot understand why. Here's my php:

$Msg=mysql_real_escape_string(htmlspecialchars($_POST['messaggio']));
if(substr($Msg,0,1 == "§")){echo $Msg;}

The output didn't show §Test that's the thing I wrote on input form, i think that this have not sense. Thank you again for your help.

adeneo · Accepted Answer · 2014-01-22 19:20:50Z

3

You didn't close substr

if( substr($Msg, 0, 1) == "§" ) {
     echo $Msg;
}

answered Jan 22, 2014 at 19:20

adeneo

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Comments

Andrew · Accepted Answer · 2014-01-22 21:19:32Z

0

mysql_real_escape_string() only works if you have a connection open to the database, or if it can open one. Assuming that is your whole code, it's probable you do not have such a connection, so it is returning false.

answered Jan 22, 2014 at 21:19

Andrew

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1 Comment

Priya Over a year ago

I checked the open connection path is correct and i tried to delete mysql_real_escape_string() :)

Priya · Accepted Answer · 2014-01-23 14:00:35Z

0

Found a solution using mb_string accuratly.

answered Jan 23, 2014 at 14:00

Priya

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