My question is a variation to this one. I can't seem to figure this one out.
given = "{abc, xyz}, 123, {def, lmn, ijk}, {uvw}, opq"
expected = ["{abc, xyz}", "123", "{def, lmn, ijk}", "{uvw}", "opq"]
As in the above example, an item in the expected could be a {..., ...} or just another string.
Many thanks in advance.
I think the following regexp fit the job. Howevever you don't have to have nested curly bracket (nested curly bracket can't be parsed using regular expression as far as I know)
>>> s= "{abc, xyz}, 123, {def, lmn, ijk}, {uvw}, opq"
>>> re.findall(r",?\s*(\{.*?\}|[^,]+)",s)
['{abc, xyz}', '123', '{def, lmn, ijk}', '{uvw}', 'opq']
\{.*?\} to \{[^}]*\}. It avoids the non-greedy match (which might be slower) and it matches even if the string contains newlines. Your current solution fails to match things like {abc,\nxyz}.given = "{abc,{a:b}, xyz} , 123 , {def, lmn, ijk}, {uvw}, opq"
#expected = ["{abc, xyz}", "123", "{def, lmn, ijk}", "{uvw}", "opq"]
tmp_l = given.split(',')
tmp_l = [i.strip() for i in tmp_l]
result_l = []
element = ''
count = 0
for i in tmp_l:
if i[0] == '{':
count += 1
if i[-1] == '}':
count -= 1
element = element + i + ','
if count == 0:
element = element[0:-1]
result_l.append(element)
element = ''
print str(result_l)
this one can handle nested curly bracket, although it seems not so elegant..
Does the following not provide you with what you are looking for?
import re
given = "{abc, xyz}, 123, {def, lmn, ijk}, {uvw}, opq"
expected = re.findall(r'(\w+)', given)
I ran that in Terminal and got:
>>> import re
>>> given = "{abc, xyz}, 123, {def, lmn, ijk}, {uvw}, opq"
>>> expected = re.findall(r'(\w+)', given)
>>> expected
['abc', 'xyz', '123', 'def', 'lmn', 'ijk', 'uvw', 'opq']
You can use the below regex to do that. Rest is same as the similar link you provided.
given = "{abc, xyz}, 123, {def, lmn, ijk}, {uvw}, opq"
regex = r",?\s*(\{.*?\}|[^,]+)"
print re.findall(regex,given)
OP: ['{abc, xyz}', '123', '{def, lmn, ijk}', '{uvw}', 'opq']
Just import the re module. and do the same as the link says.
It will match anything inside the curly braces { } and any string.
