So I have a pointer to a 2D array like so:
int board[3][5] = { 3, 5, 2, 2, 1, 3, 4, 34, 2, 2, 3, 4, 3, 223, 923 };
int* ptr[sizeof(board[0]) / sizeof(board[0][0])] = board;
I'm trying to follow this example. But for some reason I'm getting the error:
IntelliSense: initialization with '{...}' expected for aggregate object
Any idea what the problem is?
Assign pointer to the first element of the array like below
int (*ptr)[5] = board;
Note: Column size [5] in the pointer declaration should be equal to the original 2 dimension array column size [5]. Declaring row size [3] is optional.
int main() {
int board[3][5] = { 3, 5, 2, 2, 1, 3, 4, 34, 2, 2, 3, 4, 3, 223, 923 };
/*
// 3 Rows 5 Columns Matrix
int board[3][5] = { {3, 5, 2, 2, 1 },
{3, 4, 34, 2, 2 },
{3, 4, 3, 223, 923}
};
*/
// Assign pointer to the first element of the array
int (*ptr)[5] = board;
for(int i=0; i< (3*5); i++) {
std::cout<<(*ptr)[i]<<std::endl;
}
return 0;
}
A 2D array is not the same as an array of pointers. You cannot directly convert one to the other.
I just needed to put () around the *ptr. I have no idea how this fixes it but now I can do ptr[1][2].
