Parsing JavaScript Array for specific value

Question

I've a JavaScript Array like

var main = [
 { "title": "Yes", "path": "images/main_buttons/tick_yes.png"},
 { "title": "No", "path": "images/main_buttons/cross_no.png"},
]

I want to get the corresponding path value for the item which have a particular title value.

Something like

var temp = "Yes";
var result = (path value where main[0].title == temp);

I want to get the result value here.

If temp == "No", it should get me the corresponding path value.

That's not a JSON string, that's a JavaScript array (of JavaScript objects). — gen_Eric
– gen_Eric, Commented Feb 4, 2014 at 20:38
You'd need to loop over main and compare each elements .title value until you found the right one. — gen_Eric
– gen_Eric, Commented Feb 4, 2014 at 20:38
If you control the generation of this code, you could just make it an associative array, like var arr = ["yes":"someval","no","someotherval"] and access them with arr["yes"] — MaxPRafferty
– MaxPRafferty, Commented Feb 4, 2014 at 20:42

Ram · Accepted Answer · 2014-02-04 20:50:40Z

5

You can use the Array.prototype.filter method:

var result = main.filter(function(o) {
    return o.title === temp;
});

var path = result.length ? result[0].path : null;

Please note that older browsers do not the support the .filter() method. However, you can use a polyfill.

edited Feb 4, 2014 at 20:50

answered Feb 4, 2014 at 20:38

Ram

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Comments

adeneo · Accepted Answer · 2014-02-04 20:45:09Z

1

I'd do it like this

function getPath(title, arr) {
    for (var i=arr.length;i--;) {
        if (arr[i].title == title) return arr[i].path;
    }
}

called like

getPath('Yes', main); // returns the path or undefined

FIDDLE

answered Feb 4, 2014 at 20:45

adeneo

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Comments

MaxPRafferty · Accepted Answer · 2014-02-04 20:52:41Z

1

Here is one way:

var myItem = (function(arr, val){
  for(var item in arr){
    if(!arr.hasOwnProperty(item) && arr[item].title == val){
      return arr[item];
    }
  }
  return null;
})(myJSArray, "valueToMatch");

answered Feb 4, 2014 at 20:52

MaxPRafferty

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