PHP function like array_replace() but does not add unknown keys

Question

I have an associative array that holds the settings of my object. I also have a function that allows the user to override these setting by passing an associative array of replacement settings. I can use array_replace() however I don't want any values with unknown associative array keys to be added to the settings.

e.g.

$settings = array(
    'colour' => 'red',
    'size' => 'big'
);

$settings = array_replace( $settings, array(
    'size' => 'small',
    'weight' => 'heavy'   
) );

I want settings to produce:

Array
(
    [colour] => red
    [size] => small
)

Instead I get this:

Array
(
    [colour] => red
    [size] => small
    [weight] => heavy
)

Why are you merging if you just want to override?

putvande
– putvande

2014-02-05 22:29:41 +00:00
Commented Feb 5, 2014 at 22:29 — putvande
– putvande, Commented Feb 5, 2014 at 22:29
Oops I meant array_replace();

McShaman
– McShaman

2014-02-05 22:46:52 +00:00
Commented Feb 5, 2014 at 22:46 — McShaman
– McShaman, Commented Feb 5, 2014 at 22:46

Community · Accepted Answer · 2023-11-17 20:08:53Z

3

First you need to filter out unwanted items with array_intersect_key.

$settings = array(
    'colour' => 'red',
    'size' => 'big'
);

$new_settings = array(
    'size' => 'small',
    'weight' => 'heavy'   
);

$settings = array_merge($settings, array_intersect_key($new_settings, $settings));

edited Nov 17, 2023 at 20:08

CommunityBot

11 silver badge

answered Feb 5, 2014 at 22:30

Arnold Daniels

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1 Comment

McShaman Over a year ago

Exactly what I'm after

AJC · Accepted Answer · 2014-02-05 22:31:18Z

-2

You could preset what you require in an array and then just grab the values of the new array and just set what you need regardless if there is any more options

function settings($array)
{
  return array(
   "colour" => $array['colour'],
   "size" => $array['size']
  )
}

$settings = settings($array);

answered Feb 5, 2014 at 22:31

AJC

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