Shell script value issue

Question

Here is my script.

#!/bin/sh
grep $ `date +%Y%m%d`/filename.txt | sed 1d

pretty simple. I am looking to be able to run the script with just a value after it, where the value should replace the "$", such as:

bash-4.1$ ./script.sh | "value"

Any ideas on how I can do this?

Welcome to Stack Overflow. Please read the About page soon. The notation ./script.sh | "value" will run your script with no arguments and send the standard output to a program value. You can use ./script.sh "value" to pass value as $1 to the shell script (so you'd replace the $ with $1). If you want to search for a pipe symbol followed by 'value', then you'd need ./script.sh '| value' with the pipe inside quotes. — Jonathan Leffler
– Jonathan Leffler, Commented Feb 14, 2014 at 15:16
...by the way, if you want a good place to start learning bash (rather than guessing at syntax), I'd suggest mywiki.wooledge.org/BashGuide — Charles Duffy
– Charles Duffy, Commented Feb 14, 2014 at 15:54

Charles Duffy · Accepted Answer · 2014-02-14 15:10:07Z

2

Use $1, and run it as ./yourscript value.

That is to say:

#!/bin/sh
grep -e "$1" "$(date +%Y%m%d)/filename.txt"

...and...

$ ./yourscript "value"

The pipe construct isn't appropriate here -- it's used when you connect the output of one process to the input of another.

answered Feb 14, 2014 at 15:10

Charles Duffy

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